I'm guessing your problem is this:
y³ - 9y² + y - 9 = 0
right?
In solving this problem, I recommend doing this:
y³ - 9y² + y - 9 = 0
Factor out a y² from the first two numbers in the problem:
y²(y - 9) + (y - 9) = 0
Separate the parentheses which means y - 9 goes on one side. The y² added a one since it came from the + 1 in the middle of expression. When you're separating parentheses like this you just take the outside numbers and combine them together. Since + 1 came from the outside of the (y - 9) and y² also was sitting on the outside of (y - 9) combine them to make y² + 1. Like this:
(y² + 1)(y - 9) = 0
Now separate your two parentheses to two separate problems:
(y² + 1) = 0 and (y - 9) = 0
Now you're y² + 1 will equal:
y² = -1
y = √-1 <-- This number doesn't exist so it will be an imaginary number (i). If you guys didn't learn that in your class I recommend just leaving it as i for that part.
Now solve y - 9 = 0:
y = 9 <-- Since we added nine to both sides to get this.
So you're final answer should be y = i and 9
If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.
Answer:
-69x-66
Step-by-step explanation:
1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?
2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;
3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;
4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.
Hi there!
So -5 1/2 + 7 3/4 is
Improper fraction: 9/4
Decimal: 2.25
Mixed Number: 2 1/4
66 minutes is the correct answer
