8. If and m<1=135, use the figure to complete the chart.

Simplify this expression. If it is already simplified, then write it as it is. 4t^2 + 10t

AleksAgata [21]

Answer:

Already simplified.

Step-by-step explanation:

The only way to simplify an expression is to combine like terms. Like terms is where the variables are exactly the same. t^2 is not the same as t. Thus, cannot combine them, so the expression is already simplified,

4 0

3 years ago

Michael goes through the same traffic light each day on his way home from work. This year, the traffic light has been green 28 t

ASHA 777 [7]

Answer:

y = 12

Step-by-step explanation:

Given

Green = 28

Red = 35

Yellow = y

Prediction of yellow = 16 of 100

Required

Determine y

First, we need to calculate the probability of yellow.

Probability of yellow =

Probability = Yellow/Total

Where

Total = Yellow + Red + Green

Total = y + 35 + 28

Total = y + 63

So,

Probability = y/(y + 63)

Also, the prediction of yellow is 16 out of 100.

Represent this as probability.

Probability = 16/100

Equate both expressions to solve for y

y/(y + 63) = 16/100

y/(y + 63) = 0.16

Multiply both sides by (y + 63)

y = 0.16(y + 63(

y = 0.16y + 10.08

Collect like terms

y - 0.16y = 10.08

0.84y = 10.08

Solve for y

y = 10.08/0.84

y = 12

4 0

3 years ago

Determne the domain of the qraph shown. A) 0 8 B) 10, 24 C) 0 20 D 0 10 E) 0 12

Blababa [14]

I think it’s a... I think it’s a carrot

3 0

4 years ago

The upper-left coordinates on a rectangle are (-4,4), and the upper-right coordinates are (4,4).The rectangle has an area of 8 s

maw [93]

Answer:

Then the coordinate of point $C$ is $(4,3)$ , and the coordinate of point $D$ is $(-4,3)$ .

Step-by-step explanation:

Given that,

The upper-left coordinate on a rectangle is $(-4,4)$ .

The upper-right coordinate on a rectangle is $(4,4)$ .

Area of rectangle is $8$ square unit.

Let, $ABCD$ is a rectangle.

The coordinate of point $A$ is $(-4,4)$ and the coordinate of point $B$ is $(4,4)$ .

Diagram of rectangle $ABCD$ is shown below:

Now,

$AB=$ $\sqrt{(4+4)^{2}+(4-4)^{2} }$

$=\sqrt{(64+0)}$

$=\sqrt{64}$

$= 8\ unit$

∵Area of rectangle = Length $\times$ Breadth

$8$ square unit = $8\ unit$ $\times Breadth$

∴ Breadth $=1\ unit$

$BC=\sqrt{(4-4)^{2}+(y-4)^{2} }$

$=\sqrt{(y-4)^{2} }$

⇒ $1$ $=\sqrt{(y-4)^{2} }$

squaring both sides, we get

⇒ $1=(y-4)^{2}$

⇒ $(y-4)$ = ± $1$

∴ $y=3$

Then the coordinate of point $C$ is $(4,3)$ , and the coordinate of point $D$ is $(-4,3)$ .

8 0

4 years ago

Read 2 more answers

a rectangular prism has a height of 12 centimetres and a square base with sides measuring 5 centimetres, a pyramid with the same

alexandr402 [8]

Description:

The base of the prism is a square with sides measuring 5 cm, so its area is

(5cm)*(5cm)= 25 square cm

So the volume of the prism, in cubic cm, is

25*12=300

The volume of a pyramid is (1/3)(area of base)(height) .

It is 1/3 of the volume of a rectangular prism with the same base and height.

So the volume of the pyramid in this problem, in cubic cm, is

1/3*300=100

So the volume of the space outside the pyramid but inside the prism, in cubic cm, is

300-100= 200

Answer: =200

Please mark brainliest

Hope this helps.

3 0

3 years ago