Using a Graph we can determine the greatest area the rectangle can have using the midpoint between the two w-intercepts.
Answer:
ΔABD ≅ ΔACD by SAS, therefore;
by CPCTC
Step-by-step explanation:
The two column proof is presented as follows;
Statement
Reason
ABCD is a trapezoid
Given
Given
Definition of a trapezoid
ABCD is an isosceles trapezoid
Left and right leg are equal
∠BAD ≅ ∠CDA
Base angle of an isosceles trapezoid are congruent
Reflexive property
ΔABD ≅ ΔACD
By SAS rule of congruency
CPCTC
CPCTC; Congruent Parts of Congruent Triangles are Congruent
SAS; Side Angle Side rule of congruency
Answer:

Step-by-step explanation:
The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.
So, the distance from A to O AO = 90 miles and BO = 120 miles.
Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:
(1)


If we take the derivative of the equation (1) we could find the change of the distance between planes.


Finally,

I hope it helps you!
Rectangle:
P = 2 (L+W) but length is 2 meters longer than wide
then L = W + 2, So
P = 2 (L + W)
24 = 2(W+2+W)
24 = 2 (2 + 2W)
24 = 4 + 4W
So 4W = 24 -4 =20
W = 20/4= 5, L = 5+2= 7
Double check
24 = 2*(5+7) = 2 *12 = 24
Answer:
E, 297.1
Step-by-step explanation:
First, find the area of the triangle using the formula a= (bh) / 2
Base x height would be 16 x 12, which is 192
192 / 2 is 96 sq meters
Then, find the area of the circle using the formula a= Pi (r^2)
If the diameter is 16, the radius would be 8 because you divide by 2
8^2 is 64, 64 times Pi is approximately 201.1
Finally, add the areas together, 96 + 201.1 is 297.1 or E