What is the answer?

Mathematics

1 answer:

trasher [3.6K]2 years ago

7 0

Answer:

the first one

Step-by-step explanation:

because they are adjacent on a straight line

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Rewrite as a power 1 7/9

Morgarella [4.7K]

Answer:

$1\frac{7}{9} =\frac{16}{9} =[\frac{4}{3}] ^{2}$

Step-by-step explanation:

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3 years ago

A skier needs to buy new ski poles during a ski trip to utah . The price of the poles is $24 and the sales tax is 4.7%. What is

leva [86]

$total\ cost=\ price\ of\ poles+sales\ tax\\\\
total\ cost=24+4.7\%*24=24+0.047*24=24+1,128\\\\=25.128\approx25.13\$\\\\
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3 years ago

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Genrish500 [490]

Answer:

-7, -6, -4, -2, 0, 2, 5, 7, 8, 9

Step-by-step explanation:

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3 years ago

Quando existe, dizemos que a solução de um sistema de equações lineares é o conjunto ordenado de números que satisfaz todas as e

QveST [7]

X representa o numero das suas respostas certas.
y represnta o numero das suas respostas erradas.
O total de perguntas é 25, portanto
x + y = 25

Agora tratamos do dinheiro.
Começa com R$ 500,00
Pelas x respostas certas, recebe 200x.
Pelas y respostas errads perde 150y.
O total de dineheiro inicial mais os ganhos menos as perdas são iguais a
R$ 600,00, portanto
500 + 200x - 150y = 600
200x - 150y = 100
20x - 15y = 10

Temos um sistema de duas equações com duas variaveis.

x + y = 25
20x - 15y = 10

15x + 15y = 375
+ 20x - 15y = 10
---------------------------
 35x = 385
 x = 11

x + y = 25

11 + y = 25

y = 14

Resposta: Errou 14 perguntas.

5 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$