There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19
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Solution:</u></h3>
Given that, There are two numbers whose sum is 64.
Let the number be a and b in which a is bigger.
Then, a + b = 64 ------ eqn (1)
The larger number subtracted from 4 times the smaller number gives 31.
4 x b – a = 31
4b – a = 31 ----- eqn (2)
We have to find the numbers.
So, from eqn (2)
a = 4b – 31
Subatitute a in (1)
4b – 31 + b = 64
On solving we get
5b = 64 + 31
5b = 95
b = 19
So, b = 19, then eqn 1
a + 19 = 64
On simplification,
a = 64 – 19
a = 45
Hence, the two numbers are 45 and 19
Answer:
C.
Step-by-step explanation:
I can explain in comments if needed, but c is the correct answer :)
Answer:
$4.25
Step-by-step explanation:
4 quarters is 1 dollar
1 nickel is 5 cent
14 divided by 4 = 3.5
3.5 + 5 times 5 = $4.25
<span>52√+23√ = 4.79
Approx 5.1 is the answer.
Hope that helps. -UF aka Nadia
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Using elimination, we add the equations, but this time from left to right. This process wants to elimination a variable. So 2x plus -2x equals 0. Moving on the next variable, 6y plus -y is 5y. On to the last variable, 18 plus 12 is 30. So we have this equation, 5y=30. 30/5 is 6, so y=6. We plug 6 into y in one of the equations you choose. In this case, I'm going to use the first equation. Plugging 6, we have this equation, 2x plus 36 is 18. 18-36 is -18. We then have this equation, 2x=-18. We know -9 times 2 is -18, so our x value is -9, So, our y=6, and our x=-9.
