Question

Write the equation of the line that passes through (7,6) and (-1,2) in slope intercept form​

Answer 1

The equation of line passing through (7,6) and (-1,2) in slope intercept form is:

$y=\frac{1}{2}x+\frac{5}{2}$

Step-by-step explanation:

Given

(x1,y1) = (7,6)

(x2,y2) = (-1,2)

The general form of slope-intercept form of equation is:

$y=mx+b$

We have to find the slope first

$m=\frac{y_2-y_1}{x_2-x_1}\\\\m=\frac{2-6}{-1-7}\\\\m=\frac{-4}{-8}\\\\m=\frac{1}{2}$

Putting the value of slope in the equation

$y=\frac{1}{2}x+b$

To find the value of b, putting (-1,2) in the equation

$2=\frac{1}{2}(-1)+b\\2=-\frac{1}{2}+b\\2+\frac{1}{2}=b\\b=\frac{4+1}{2}\\b=\frac{5}{2}$

Putting the value of m and b in equation

$y=\frac{1}{2}x+\frac{5}{2}$

The equation of line passing through (7,6) and (-1,2) in slope intercept form is:

$y=\frac{1}{2}x+\frac{5}{2}$

Keywords: Slope intercept form, slope

Learn more about equation of line at:

• brainly.com/question/2397962
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