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2 years ago

Twenty different video games showing alcohol use were observed. The duration times of alcohol use (in seconds) were recorded.

Mathematics

1 answer:

Crazy boy [7]2 years ago

8 0

Answer:

Degree of freedom = 19

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 20

For a t-test hypothesis it was claimed that the population mean is greater than 89 second.

1) df

Df denotes the degree of freedom.

The Degrees of Freedom refers to the number of values involved in the calculations that have the freedom to vary.

2) Degree of freedom = n - 1

where n is the sample size

Degree of freedom = 20 - 1 = 19

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Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

6 0

2 years ago

Determine if a triangle with the given dimensions is a right triangle. If it is, which angle is the right angle?

Arte-miy333 [17]

To determine if the triangle is a right triangle, we use the Pythagorean theorem to test or see if the data agrees. We do as follows:

c² = a² + b²
10² = (5√3)² + 5²
100 = 75 + 25
100 = 100

Therefore, the triangle with the given measurements is a right triangle. The angle that would have a right angle is angle BAC. Hope this answers the question. Have a nice day. Feel free to ask more questions.

6 0

2 years ago

Help me please i need help

scZoUnD [109]

It’s D
the x in f(x) is the x axis
look at 3 in the x axis
you see that it goes up to 8 y-axis
f(3)= 8

4 0

1 year ago

A cat rescue service found homes for 40 cats in 5 weeks. What was the rate of cats being placed per week? Which ratio is equal t

ExtremeBDS [4]

A. 8 cats per week. if you simplify 40/5, it equals 8/1

7 0

3 years ago

Read 2 more answers

0.9 of Karen's Science score is equal to 0.75 of her Math score and 0.8 of her Chemistry score. Given that Karen scored 96 marks

DochEvi [55]

You have to formulate equations for this problem.

Let S = Science score

M = Math score

C = Chemistry score

To illustrate the given:

0.9S = 0.75M

0.9S = 0.8C

You are given that Karen’s Math score is 96 marks. You have to substitute the Math score to the first equation.

0.9S = 0.75(96)

0.9S = 72

S = 80

Therefore, Karen’s Science score is 80. Now, you have to substitute the Science score to the second equation.

0.9(80) = 0.8C

0.8C = 72

C = 90

So, Karen’s Chemistry score is 90.

Therefore, the total score of the 3 subjects is 266 (96 + 80 + 90).

5 0

3 years ago

Twenty different video games showing alcohol use were observed. The duration times of alcohol use ​(in seconds) were recorded.

Twenty different video games showing alcohol use were observed. The duration times of alcohol use (in seconds) were recorded.