The significance of the point where the pressure drops to zero is that at that point the gases would completely show ideal behavior.
<h3>What is the gas law?</h3>
The gas laws can be used to describe the behavior of the ideal gases. It is pertinent to note that the ideal gas law can strictly be applied to gases that are at a high temperature and low pressure.
We can be able to find the temperature when the pressure is equal to zero either be the use of the equation line or by experiment. In that case, we would be able to obtain the point at which the pressure drops to zero.
The significance of the point where the pressure drops to zero is that at that point the gases would completely show ideal behavior.
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Answer:- 6984 kJ of heat is produced.
Solution:- From given information, 1367 kJ of heat is produced by the combustion of 1 mole of ethanol. We are asked to calculate the heat produced by the combustion of 235.0 g of ethanol.
Let's convert given grams to moles and multiply by the heat produced by one mole of ethanol to get the total heat produced. Molar mass of ethanol is 46 grams per mole. The set will be:
= 6984 kJ
So, 6984 kJ of heat is produced by the combustion of 235.0 g of liquid ethanol.
We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:
ATP + H₂O → ADP + HPO₄²⁻
We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:
ΔGrxn = ΔG°rxn + RTlnQ
We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:
Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001
Now we can use the above formula to solve for ΔGrxn.
ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol
The value of ΔGrxn = -54.3 kJ/mol.
Answer:
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