Answer:
Roughly C100 H140 N3 O
Explanation:
Gilsonite is a bituminous product that resembles shiny black obsidian.
It contains more than 100 elements.
Its mass composition varies but is approximately 84 % C, 10 % H, 3 % N, and 1 % O.
Its empirical formula is roughly C100 H140 N3 O.
Answer:
1.25 hours or 75 minutes or 1 hour and 15 minutes
Explanation:
Answer:
B. Equal amounts of all gases have the same volume at the same
conditions
Explanation:
Amedo Avogadro found the relationship between volume of a gas and the number of molecules contained in the volume.
The law states that "equal volumes of all gases at the same temperature and pressure contains equal number of molecules or moles".
The law describes the behavior of gases when involve in chemical reactions. It enables one to change over at will in any statement about gases from volumes to molecules and vice versa.
So, the right option is B which implies that equal amounts of all gases have the same volume at the same conditions.
It is a trial aimed to reduce bias during an experiment. An example would be a sugar pill, something that has no real effect so that the results of the true trial can accurately be compared. Its like a control group.
Answer:
grams H₂O produced = 8.7 grams
Explanation:
Given 2C₂H₆(g) + 7O₂(g) => 4CO₂(g) + 6H₂O(l)
7g 18g ?g
Plan => Convert gms to moles => determine Limiting reactant => solve for moles water => convert moles water to grams water
Moles Reactants
moles C₂H₆ = 7g/30g/mol = 0.233mol
moles O₂ = 18g/32g/mol = 0.563mol
Limiting Reactant => (Test for Limiting Reactant) Divide mole value by respective coefficient of balanced equation; the smaller number is the limiting reactant.
moles C₂H₆/2 = 0.233/2 = 0.12
moles O₂/7 = 0.08
<u><em>Limiting Reactant is O₂</em></u>
Moles and Grams of H₂O:
Use Limiting Reactant moles (not division value) to calculate moles of H₂O.
moles H₂O = 6/7(moles O₂) = 6/7(0.562) moles H₂O = 0.482 mole H₂O yield
grams H₂O = (0.482mol)(18g·mol⁻¹) = 8.7 grams H₂O
