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3 years ago

13

What is a formula to find the midpoints of this figure?

1 answer:

zysi [14]3 years ago

7 0

The mid-segment of a trapezoid<span> is the line that connects the midpoints of the two nonparallel sides of the trapezoid. S</span>o, I believe, using the Trapezoid Midsegment<span> Theorem you can answer the question.

x= a+b/2
Find a, x, and y

</span>

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The manager of a snack bar buys bottled water in packs of 35 and candy bars in packs of 20. Then, she sells the items individual

cestrela7 [59]

4 packs of bottled water (35*4=140)
7 packs of candy bars (20*7=140)

8 0

3 years ago

Read 2 more answers

What is the distance between the points (2,10) and (-6, 4) on the coordinate

stellarik [79]

Answer:

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

Therefore distance s=10 units

Step-by-step explanation:

Given points are (2,10) and (-6, 4) on the coordinate plane

To distance between the given points :

The distance formula is $s=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ units

Let $(x_1,y_1)$ , $(x_2,y_2)$ be the given points (2,10) and (-6, 4) respectively

Now substituting the values in the distance formula we get

$s=\sqrt{(-6-2)^2+(4-10)^2}$

$=\sqrt{(-8)^2+(-6)^2}$

$=\sqrt{8^2+6^2}$

$=\sqrt{64+36}$

$=\sqrt{100}$

$=10$

Therefore s=10 units

The distance between the given points (2,10) and (-6, 4) on the coordinate plane is 10units

5 0

3 years ago

leonid [27]

Don’t click those links!

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3 years ago

Picture provided help!

weqwewe [10]

Answer:

A -60i - 14j

Step-by-step explanation:

u = -9i + 8j

v = 7i + 5j

2u = 2(-9i + 8j) = -18i + 16j

6v = 6(7i + 5j) = 42i + 30j

2u - 6v

(-18i + 16j) - (42i + 30j)

(-18i - 42i) + (16j-30j)

-60i - 14j

5 0

3 years ago

Please help me solve. x-(-16)=44 i know the answer i just need the work

Marat540 [252]

x+16=44

x=44-16

x=28

That is the answer

6 0

3 years ago