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s2008m [1.1K]
3 years ago
13

Two over twenty-two plus six over eleven

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

The answer is 7/11.

Here's how I got the answer:

Step 1: Simplify 2/22 to 1/11. Which leaves us with 1/11 + 6/11

Step 2: Join the denominators. Which leaves us with 1+6/11

Step 3: Add 1 and 6 to get your answer. 7/11


kirill [66]3 years ago
4 0

\frac{2}{22}+\frac{6}{11}


Simplify \frac{2}{22} to \frac{1}{11}


\frac{1}{11}+\frac{6}{11}


Both are over 11, so, just sum.


\frac{1+6}{11}

\frac{7}{11}

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The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
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Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

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Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

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And we have;

\mu_{\bar X}= 14.70

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Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
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(subtract 9x from both sides)

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The coordinates of Point D are: (-5,-8)

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