<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>
<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>
Answer:
We conclude that whoever (between Tamara and Clyda's work) may have got the answer as
after dividing
by
, would be the one who solved it correctly.
Step-by-step explanation:
Considering the expression

Lets divide the expression by 
Solution Steps:

Factorizing

Factorizing




Thus,

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as
after dividing
by
, would be the one who solved it correctly.
Keywords: expression, division
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Answer:
1/2(3)-2/3(8)
3/2-9/3
<u>3</u>-<u>9</u>
2.3
<u>9</u><u>-</u><u>3</u><u>2</u>
6
<u>-23</u>
6
Answer:
Step-by-step explanation:
Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.
We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.
I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.
The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.
i) u + 3 V
1 by 2 + 3 *minus 2
1 by 2 -6
1 - 12 by 2
- 11 by 2
ii) - 3 * 1 by 2 + 2 * -2 + 3 by 4
minus 19 by 4
Answer:
elected Council
Step-by-step explanation: