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1 year ago

9

Find the difference: 56.34 - 3.1

1 answer:

Serjik [45]1 year ago

6 0

It is D you have subtract them

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Solve equation for x 3x+4=10

Katena32 [7]

Hello!

3x + 4 = 10

3x = 10 - 4

3x = 6

x = 2

I hope this helps you! Have a lovely day!

- Mal

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2 years ago

I am doing solving by elimination for Algebra 1 and I am lost here is the question

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2 years ago

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The average daily volume of a computer stock in 2011 was ų=35.1 million shares, according to a reliable source. A stock analyst

Shtirlitz [24]

Answer:

a

The null hypothesis is $H_o : \mu = 35 .1 \ million \ shares$

The alternative hypothesis $H_a : \mu \ne 35.1\ million \ shares$

b

The 95% confidence interval is $27.475 < \mu < 37.925$

Step-by-step explanation:

From the question the we are told that

The population mean is $\mu = 35.1 \ million \ shares$

The sample size is n = 30

The sample mean is $\= x = 32.7 \ million\ shares$

The standard deviation is $\sigma = 14.6 \ million\ shares$

Given that the confidence level is $95\%$ then the level of significance is mathematically represented as

$\alpha = 100-95$

$\alpha = 5\%$

=> $\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

The value is $Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{ \sigma }{\sqrt{n} }$

substituting values

$E = 1.96 * \frac{ 14.6 }{\sqrt{30} }$

$E = 5.225$

The 95% confidence interval confidence interval is mathematically represented as

$\= x -E < \mu < \= x +E$

substituting values

$32.7 - 5.225 < \mu < 32.7 + 5.225$

$27.475 < \mu < 37.925$

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2 years ago

List three ways you can use an electric current. Describe the energy Chang that takes place

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If the two requirements of an electric<span> circuit are met, then charge will flow through the external circuit. Causing a </span> flow of electric charge to power any machine or device, etc.

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If a salesperson sells a car at a profit of $1000, how much will the commission be?

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