Find the difference: 56.34

Department s had 500 units 60% completed in process at the beginning of the period; 9,000 units completed during the period; and

Delicious77 [7]

With the concept of first in, first out method, then we can use the formula below to solve for the number of equivalent units of production for that period.

number of equivalent units of production

= Total number of units completed during that period (A) – Number of units completed in process at the beginning of the period (B) + Number of units completed at the end of the period (C)

= A – B + C

We know that,

A = 9000 units

So we solve for B and C.

B is 60% of the 500 units, therefore:

B = 0.60 * 500 = 300

C is 30% of the 600 units, therefore:

C = 0.30 * 600 = 180

Substituting the values into the equation:

number of equivalent units of production = 9000 – 300 + 180

number of equivalent units of production = 8880 units

Answer:

A. 8880

3 0

3 years ago

The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

the probability that he will be more than 76 inches tall.

(b) If two men are chosen at random from the population, find

the probability that

(i) both of them will be more than 76 inches tall;

(ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{S.D}$ ) > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{76 - 69.7}{2.8}$ )

= P(Z > 2.25)

= 1 - P(Z ≤ 2.25)

= 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

= 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

$\frac{S.D}{\sqrt{N} }$ = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } }$ )) > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- 69.7)}{1.979899 }$ ))

= P(Z > 3.182)

= 1 - P(Z ≤ 3.182)

= 0.0007

⇒P(Y > 76) = 0.0007

6 0

3 years ago

Find the Arithmetic mean between 6 and 12

mafiozo [28]

Step-by-step explanation:

Arithmetic mean

$A.M. = \frac{6 + 12}{2} = \frac{18}{2} = 9 \\$

6 0

3 years ago

Read 2 more answers

I can’t seem to find the value of n in this peoblem

Annette [7]

Answer:

9

Step-by-step explanation:

you can always use guess-and-check:

124 seems rather high

(6)P(2) = 6!/4! = 6x5 ≠ 72

(9)P(2) = 9!/7! = 9x8 = 72

3 0

2 years ago

Read 2 more answers

What does 3ˣ + 4·3ˣ⁺¹ = a. 13·3ˣ⁺¹ b. 5·3ˣ⁺¹ c. 5·3²ˣ⁺¹ d. 13·3ˣ

Crazy boy [7]

Answer:

D. 13*3^x

Step-by-step explanation:

$3^x +4*3^x^+^1= \\3^x+4*3(3^x)=\\3^x(1+[4*3])=\\3^x(1+12)=\\3^x(13)=\\13*3^x$

3 0

3 years ago

Find the difference: 56.34 - 3.1​

Find the difference: 56.34 - 3.1