<span>Ending Amt = Bgng Amt * e ^-0.03t
In this equation, the "-0.03" is the decay factor or "k"
We can now solve for half-life by this equation:
</span>t = <span>(<span>ln [y(t) ÷ a]<span>)<span> ÷ -k (we can say beginning amount = 200 and ending amount = 100
</span></span></span></span>t = <span>(<span>ln [200 ÷ 100]<span>)<span> ÷ -k
</span></span></span></span>t = <span>(<span>ln [2]<span>)<span> ÷ -k
</span></span></span></span>t = 0.69314718056<span> ÷ --.03
t =</span><span><span><span> 23.1049060187
</span>
about 23 years
</span></span>
Formula for the area of a quarter circle: A = (pi x r^2) / 4
A = (pi x 2^2) / 4
A = (pi x 4) / 4
A = 4pi / 4
A = 1pi = 3.14 square miles
Hope this helps! :)
Answer:
15 = x
Step-by-step explanation:
A.
-1:
(-1,1)
0:
(0, 2)
1:
(1, 4)
2:
(2, 8)
3:
(3,16)b.
To graph the equation, simply go through the points (-2, 0.5), (-1, 1), (0,2), (1,4), (2,8), and (3,16). Make sure you never go below 0 on the x-axis, because there's an asymptote there.
Hope this helps!