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Tomtit [17]
3 years ago
8

The formula c = 5p + 210 relates c, the total cost in dollars of hosting a birthday party at a skating rink, to

Mathematics
1 answer:
Lesechka [4]3 years ago
5 0
It would be 31 because if they are willing to spend 365 on the party then you’d replace the c with 365 and then subtract 210 from 365 and then divide 5 to get the variable by itself
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10. If ∆POW ≅∆BAM, what are the congruent corresponding parts? (Hint: You should name three pairs of congruent sides and three p
Anon25 [30]
<span> If ∆POW ≅∆BAM

</span>congruent  <span>sides:
</span>PO = BA
OW = AM
PW = BM

<span>congruent </span>angles:
<P = <B
<O = <A
<W = <M
6 0
3 years ago
Please help. quickly if possible
Dafna11 [192]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Jackie is a toll booth employee. One day, she wrote the expression:0.75m= 15.75She let m represent the number of motorcycles tha
Brrunno [24]

Answer:

21


Step-by-step explanation:

The expression Jackie came up with is:

0.75m = 15.75.

To get the value of m, we divide both sides by 0.75

0.75m = 15.75.

0.75m/0.75 = 15.75/0.75

m = 1575/75

     = 21


4 0
3 years ago
Find the volume of the region between the cylinder z=3y^2 and the xy-plane that is bounded by the planes x=0,x=1 ,y=-1 and . z =
son4ous [18]

Answer:

The volume of the region V = 2

Step-by-step explanation:

Given that:

z_1 = 3y^2 ;

where initially;

z_o = 0; \ x_o = 0;  \ x_1 = 1; \  y_o= -1;  \ y_1 = 1

The volume of the region is given by a triple which is expressed as:

V = \int_x \int_y \int_z \ dz \ dy \ dx

V = \int \limits ^{x_1 = 1}_{x_o=0}  \int \limits  ^{y_1 = 1}_{y_o=-1}    \int \limits ^{z_1 = 3y^2}_{z_o=0}  \ dz \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}    \int \limits ^{3y^2}_{0}  \ dz \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}   \Bigg [z \Bigg]^{3y^2}_{0} \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}   \Bigg [3y^2 \Bigg]  \ dy \ dx

V = \int \limits ^{1}_{0}   \Bigg [\dfrac{3y^3}{3} \Bigg]^1_{-1}   \ dx

V = \int \limits ^{1}_{0}   \Bigg [\dfrac{3(1)^3}{3}- \dfrac{3(-1)^3}{3} \Bigg]   \ dx

V = \int \limits ^{1}_{0}   \Bigg [1-(-1)\Bigg]   \ dx

V =2  \Bigg [x \Bigg] ^1_0

V = 2

Thus, the volume of the region is 2

3 0
3 years ago
Consider the parallelogram.
KIM [24]
In a parallelogram, opposite angles are equal, since you are given that this is a parallelogram, you know that opposite angles are indeed equal. That would mean that 125 is equal to x and 55 is equal to y. If you want to check your work, the interior angles of a quadrilateral sum to 360, 125+125+55+55 is 360, so you're good.
4 0
3 years ago
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