Ask question

Ask question

All categories

2 years ago

9

Please help. quickly if possible

2 answers:

Mars2501 [29]2 years ago

7 0

Answer is D

1cm = 50m so (6.3 x 50) + (4.7 x 50) = 630meters

Hope that helps :D

Dafna11 [192]2 years ago

6 0

Answer:

B

Step-by-step explanation:

You might be interested in

A student obtain 85 ,90,95,100and 75 in his maths test (1). What is the average of his test grades?

netineya [11]

Answer:

89.

Step-by-step explanation:

There are 5 scores.

So the Average = (85 + 90+95+100+ 75)/5

= 445/5

= 89.

8 0

2 years ago

Read 2 more answers

Twenty one is no less than the sum of a number and -2

Gala2k [10]

$x+(-2)=21
$
get rid of -2 by subtracting it from 21
$x+(-2)=21-(-2)$
Now you get your answer
$x=23$
Hope this helps! :)

4 0

3 years ago

An airplane travels at a constant speed of 300 miles per hour. How far, in miles, will the airplane travel in 20 minutes?

Strike441 [17]

Answer:

100 miles in 20 minutes.

Step-by-step explanation:

300/60 = x/20

x = 300/60 * 20

x = 100

7 0

2 years ago

Dafna1 [17]

Answer:

20

Step-by-step explanation:

2/3 want to go

If there are 30 people, we can find our answer pretty easily as 30 is 10 times more than 3.

2/3 = 20/30

So 20 people would like to go :O

Hope this helps, have a nice day :))

6 0

2 years ago

Read 2 more answers

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

2 years ago