Question

Which is the equation of a line that has a slope of 4 and passes through point (1, 6)?

Answer 1

Answer: $y=4x+2$

Step-by-step explanation:

The equation of a line passing through (a,b) and having slope m is given by :-

$(y-a)=m(x-b)$

Given : A line is passing through (1, 6) and has slope = 4

Then , the equation of a line passing through (1,6) and having slope 4 is given by :-

$(y-6)=4(x-1)\\\\\Rightarrow\ y-6=4x-4\\\\\Rightarrow\ y=4x-4+6\\\\\Rightarrow\ y=4x+2$

Hence, the equation of a line passing through (1,6) and having slope 4 is $y=4x+2$

Answer 2

Y - 6 = 4(x - 1)
y - 6 = 4x - 4
y = 4x + 2

answer
c.y = 4x + 2