Considering the place value of the digit 9, in the first number, the decimal value of 9 is thousands. In the second number, the decimal value of 9 is hundredths. The conclusion we are drawing is: The second decimal is 10 times larger than the first one
Answer:
Step-by-step explanation:
First you need to convert it to a linear expression.
3x - y = 4
+3x +3x
-1y = 3x + 4
--- ----- -----
-1 -1 -1
y = -3x -4
6x - 2y = 7
-6x -6x
-2y = -6x + 7
---- ----- -----
-2 -2 -2
y = 3x - 3.5
-3x - 4 = 3x - 3.5
+3x +3x
-4 = 6x - 3.5
+3.5 +3.5
-0.5 = 6x
----- -----
6 6
-0.5
------ = x
6
You are told to choose the choices equal to T(8). T(8) means that you need to find the possible ways to write the y-value when n = 8, since 8 is being substituted in for "n."
1) First, plug in n = 8 into the equation you're given, <span>T(n) = 4n - 5:
T(8) = 4(8) - 5
T(8) = 32 - 5
T(8) = 27
That is answer choice C, making choice C correct. You can eliminate choice B, since 27 </span>≠ 37.
2) Check answer choice A. Is T(5) + T(3) = 27? T(5) means you need to plug in 5 for n. T(3) means you need to plug in 3 for n.
T(5) + T(3)
= [4(5) - 5] + [4(3) - 5]
= [20-5] + [12-5]
= 15 + 7
= 22
Since 22 ≠ 27, you can eliminate choice A.
3) Check answer choice D. Is T(7) + 4 = 27? T(7) means you need to plug in 7 for n.
T(7) + 4
= [<span>4(7) - 5] + 4
</span>= [28 - 5] + 4
= 23 + 4
= 27
Since 27 = 27, answer choice D is also correct!
--------
Answer: Choice C (27) and Choice D (T(7) + 4)
Answer:
4/3
Step-by-step explanation:
i took the quiz hehe
Answer:
Number of cards at week n = 10,000(0.85)^(n-1).
At week 6 Dylan has 4437 cards.
Step-by-step explanation:
At the start of week 1 he had 10,000 = 10,000(0.85)^0 cards.
So at the start of week 2 he had 10,000(0.85)^(2-1) cards.
Number of cards for week n = 10,000(0.85)^(n-1).
Number of he will have at the start of the 6th week
= 10,000(0.85)^(6-1)
= 4437 cards (answer).
