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andrew11 [14]
3 years ago
13

How long does it take a rocket traveling at a constant velocity of 100 m/s to climb from 200m to 1200m

Physics
1 answer:
neonofarm [45]3 years ago
7 0

Answer:

10 seconds

Explanation:

you multiply 100 by 10 in order to get 1000m

you add 200m to 1000m to get to the maximum of 1200m

since you travel at 100 per second, it took 10 seconds

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Even if all stars were the same distance from Earth, their absolute magnitude and
k0ka [10]

Answer: True


hope this helps!

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2 years ago
Blueberries cost $4.00 per pound, how many blueberries can you buy for $1.00
melomori [17]

Answer:

1/4 of a pound or 4 ounces

Explanation:

4.00 = 1 pound (= 16 oz)

4.00 / 16 oz = 4

16 /4 = 1/4 or 4 ounces

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3 years ago
a person has gotten a new job with a much higher salary. he plans to spend his extra money on a new car and a great stereo syste
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just took the quiz and got it right

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Read 2 more answers
Which pair of triangles can be proven congruent by the hl theorem?
hoa [83]

The pairs of triangles that can be proven congruent by the hl theorem is the right angled triangle.

<h3>What is mearnt be the HL theorm?</h3>

The HL theorem is also known as the Hypothenus Leg theorem, it states that "the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent."

Learn more about the postulates of the HL theorem here:

brainly.com/question/25922842

4 0
3 years ago
A cricket ball has mass 0.155 kg. If the velocity of a bowled ball has a magnitude of 35.0 m/s and the batted ball's velocity is
FinnZ [79.3K]

Answer:

Magnitude of change in momentum = 4.65 kg.m/s

Magnitude of impulse = 4.65 kg.m/s

Magnitude of the average force applied by the bat = 1550 N

Explanation:

Mass of the cricket ball, m = 0.155 kg

Initial velocity of the ball, u = 35.0 m/s

final velocity of the ball after hitting the bat, v = 65.0 m/s

Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s

Now,

Magnitude of change in momentum = Final momentum - Initial momentum

or

Magnitude of change in momentum = ( m × v ) - ( m × u )

or

Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )

or

Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s

Now, Magnitude of impulse = change in momentum

thus,

Magnitude of impulse = 4.65 kg.m/s

Now,

magnitude of the average force applied by the bat = \frac{\textup{Impulse}}{\textup{Time}}

or

magnitude of the average force applied by the bat = \frac{\textup{4.65}}{\textup{3}\times\textup{10}^{-3}}

or

Magnitude of the average force applied by the bat = 1550 N

6 0
4 years ago
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