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natita [175]
2 years ago
12

Even if all stars were the same distance from Earth, their absolute magnitude and

Physics
1 answer:
k0ka [10]2 years ago
4 0

Answer: True


hope this helps!

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Which statements describe a physical property of matter? Check all that apply
Galina-37 [17]
<span>The correct answer is all mentioned because all have the characteristics that apply in theories of the properties of matter and their physical behaviors, which encompass mass, temperature, smell, and volume.</span>
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4 years ago
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7 One lb of Refrigerant 134a contained within a piston–cylinder assembly undergoes a process from a state where the temperature
julsineya [31]

Answer:

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb ^ {\circ} R}

Explanation:

A) In order to solve the table it is necessary to consult tables A11-E and A10E for refrigerant R134-a

In this way we obtain that:

S_1 = S_f = 0.0648 \frac {BTU} {Lb. ^ {\circ} R}

In this way,

S_2 = S_f + x_2 (S_g-S_f) = 0.0902 + 0.5 (0.2161-0.0902)

S_2 = 0.15315 \frac {BTU} {Lb ^ {\circ} R}

In this way the entropy change is,

\Delta S = S_2-S_1 = 0.08835 \frac {BTU} {Lb. ^ {\°} R}

B) Whenever entropy yields a positive result, the process can be carried out adiabatically.

7 0
3 years ago
Planet geos in orbit a distance of 1
nadya68 [22]

Planet Geos in orbit a distance of 1 A.U. (astronomical unit) from the star Astra has an orbital period of 1 "year." If planet Logos is 4 A.U. from Astra, how long does Logos require for a complete orbit?

TB = <span>8</span> years

4 0
3 years ago
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Force Diagram
d1i1m1o1n [39]
This is a pretty long question
8 0
3 years ago
Potassium is a crucial element for the healthy operation of the human body. Potassium occurs naturally in our environment and th
Mariulka [41]

Answer:

a) 0.0288 grams

b) 2.6*10^{-10} J/kg

Explanation:

Given that:

A typical human  body contains about 3.0 grams of Potassium per kilogram of body mass

The abundance  for the three isotopes are:

Potassium-39, Potassium-40, and Potassium-41 with abundances are 93.26%, 0.012% and 6.728% respectively.

a)

Thus; a person with a mass of 80 kg will posses = 80 × 3 = 240 grams of potassium.

However, the amount of potassium that is present in such person is :

0.012% × 240 grams

= 0.012/100 × 240 grams

= 0.0288 grams

b)

the effective dose (in Sieverts) per year due to Potassium-40 in an 80- kg body is calculate as follows:

First the Dose in (Gy) = \frac{energy \ absorbed }{mass \ of \ the \ body}

= \frac{1.10*10^6*1.6*10^{-14}}{80}

= 2.2*10^{-10} \ J/kg

Effective dose (Sv) = RBE × Dose in Gy

Effective dose (Sv) =  1.2  *2.2*10^{-10} \ J/kg

Effective dose (Sv) = 2.6*10^{-10} J/kg

 

5 0
4 years ago
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