The _____ leads from the pharynx towards the lungs

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m

ddd [48]

Answer:

Velocity of electron will be $1.325\times 10^6m/sec$

Explanation:

We have given distance across the plate d = 2 mm $=2\times 10^{-3}m$

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d is distance

So $E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C$

Charge on electron $e=1.6\times 10^{-19}C$

We know that expression of velocity is given by $v=\sqrt{\frac{2qEd}{m_e}}$ , here q is charge on electron, E is electric field and d is distance

So $v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec$

8 0

4 years ago

A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow

shusha [124]

Answer:

150000000

$\dfrac{F_e}{F_g}=0.00000203873598369$

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

$1\ C=6.25\times 10^{18}\ electrons$

Number electrons is

$n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000$

The number of electrons added or removed was 150000000

Force is given by

$F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N$

The ratio is

$\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369$

The ratio is $\dfrac{F_e}{F_g}=0.00000203873598369$

Balancing the forces we get

$Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C$

The electric field required is 49050000 N/C

4 0

4 years ago

If the electrons are attracted more by the nucleus because of an additional proton, what would happen to it?

Rus_ich [418]

Answer:

orbital speed of the electrons in their orbit will increase

Explanation:

As we know that centripetal force for electrons will be due to electrostatic attraction force of electron.

So it is given as

$F_e = F_c$

so we have

$\frac{(Ze)(e)}{4\pi \epsilon_0 r^2} = \frac{mv^2}{r}$

now on the left side if the force of attraction will increase and hence there must be the change in that part of equation

So here at the same position the speed of the electron

So we can say that correct answer will be

orbital speed of the electrons in their orbit will increase

4 0

3 years ago

If the number of particles is increased in a balloon what happens to the pressure inside of it?

Klio2033 [76]

The air pressure inside the balloon increases as the number of particles increases.

8 0

3 years ago

A geothermal plant uses geothermal water (yes a liquid) extracted from beneath the Earth using drilling apparatus. The geotherma

Sophie [7]

Answer:

4.1%

Explanation:

Given that water specific heat c = 4186 J/kgC. If water is flowing with mass rate of 200kg/s and temperature is dropping from 200C to 25C. Then the thermal energy rate from the water should be

$P_i = mc\Delta t = 200*4186*(200 - 25) = 146510000
J/s$ or 146510kW

Since the turbine is only able to extract 6000kW of power, then the thermal efficiency is:

$Eff = \frac{P_o}{P_i} = \frac{6000}{146510} = 0.041$ or 4.1%

8 0

3 years ago