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Juliette [100K]
3 years ago
8

The nurse is attending to an older patient who cannot tolerate oral medication. the patient is prescribed subcutaneous therapy f

or infusion of isotonic solutions. what action does the nurse take during hypodermoclysis?
Biology
1 answer:
cricket20 [7]3 years ago
5 0
The nurse should first select an area to perform the hyphodermoclysis, outside of the elbow is usual but the back of the hand is fine too. Then the nurse must apply a tourniquet 10 cm before the selected area, so it blocks blood circulation. After feeling the vein stand out in the selected area, said area must be cleaned with an antiseptic solution. Then the nurse should introduce the needle connected to the catheter in the outstanding vein, following along the anatomy of the patient against the normal bloodstream direction, so the needle stays almost parallel to the vein while inserted. Finally the nurse must fix the needle to the arm using medical adhesive, and remove the tourniquet.
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Assume that the left ventricle of a child's heart has an EDV=90mL, and ESV=60mL, and a cardiac output of 2,400 mL/min. His SV is
Sliva [168]

Answer:

SV = 30 ml/ beat.

HR = 80.

Explanation:

The formula to calculate SV is as follows:

SV = EDV- ESV.

Here EDV = 90ml (end diastolic volume), ESV = 60ml (end systolic volume) ans SV is stroke volume.

SV = 90-60

SV = 30ml/beat.

The formula to calculate HR is as follows:

HR = CO/SV

Here, HR is heart rate, CO is cardiac output = 2,400 ml/min and SV is stroke volume = 30ml/beat

HR = 2,400/30

HR = 80.

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3 years ago
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4 years ago
The gene frequency for a dominant allele is 0.68 and the recessive allele is 0.39. What percent of the population has a homozygo
Alinara [238K]

Answer:

15.21 %

Explanation:

If we recall the basic formula of Hardy-Weinberg's equilibrium ; we have the following below:

p + q = 1

p² + 2pq + q² = 1

where;

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q = frequency of the recessive allele in the population

p² = percentage of homozygous dominant individuals

q² = percentage of homozygous recessive individuals

2pq = percentage of heterozygous individuals

Given that p= 0.68 and q = 0.39

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(0.39)² = 0.1521

= 0.1521 × 100

= 15.21 %

∴ the percentage of the population that has a homozygous recessive genotype = 15.21 %

5 0
3 years ago
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