Answer:
Nucleic acid would be responsible.
Explanation:
Answer:
All the offsprings will be black-furred (Bb)
Explanation:
This question involves a single gene coding for fur length in rabbits. The allele for black fur (B) is dominant to the allele for white fur (b). This means that a rabbit heterozygous for this gene (Bb) will have a black fur.
According to this question, a purebred black furred male (BB) is bred with a female that had the recessive white fur (bb). The parents will produce gametes as follows:
BB - B only
bb - b only
Using these gametes in a punnet square (see attached image), the genotypic proportion of the produced offsprings is as follows:
Bb, Bb, Bb, Bb
All Bb (heterozygous) means that all of the offsprings will be black-furred.
Answer:
The process depicted in the diagram above is explained below in complete details.
Explanation:
1 asexual generation
2. cytokinesis
3. karyokinesis
4.fission
(a) Amoeba
(b) in repetitious fission many elements modifications to offspring ( plasmodium ( while in amoeba only individual sections to create two separate daughter cell
(c) asexual reproduction
ii in leishmania you can totally cut three sections and it changes to a new organism and in amoeba, it can be cut wherever.
Answer:
c
Explanation:
the right thing to do is resolve the fault of the cause