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2 years ago

Jared has priced a laptop computer at two stores.

1 answer:

5 0

1525 X .15%= 228.75 1525-228.75= 1296.25
1825 * 25%=456.25=456.25 1825-456.25=1368.75
Store A has the better deal it will be cheaper

You might be interested in

given the rule s=t+3 and the starting number 0, create a table to show the first 5 terms in the sequence graph the resulting ord

IRINA_888 [86]

0= 3
1= 4
2=5
3=6
4=7
5=8
6=9
7=10

8 0

3 years ago

A 1.50 liter sample of dry air in a cylinder exerts a pressure of 3.00 atmospheres at a temperature of 25oC. Without change in t

cricket20 [7]

The answer is 4.5 l

To calculate this, we will use the Boyle's law using constant k, pressure P, and volume V:

PV = k

We can forget temperature since it is constant.

We have:

P1V1 = k

P2V2 = k

So, P1V1 = P2V2

P1 = 3 atm

V1 = 1.5 l

P2 = 1 atm

V2 = ?

_____

P1V1 = P2V2

3 atm * 1.5 l = 1 atm * V2

4.5 atm/l = 1 atm * V2

V2 = 4.5 atm l / 1 atm

V2 = 4.5 l

5 0

3 years ago

Read 2 more answers

Without solving it, determine the nature of the roots of this equation:

ycow [4]

<h2>Answer:</h2>

x = 1, -4

Step-by-step explanation:

Find the roots of x:

2 + 3

x − 4 = 0 by solving for x

6 0

3 years ago

A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$

$h(1.5)=-(0.5)(-5.5)$

$h(1.5)=2.75$

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0

2 years ago

Little Snail is going to visit his friend over at the next pond, 3 miles away. He can crawl ( 1/2. 1/3, 1/4, 3/4, 2/3 ) of a mil

KIM [24]

Solution :

It is given that Little Snail is going to visit one of his friend at the pond which is 3 miles away.

When the snail crawls 1/2 of a mile per day, it will take him, $1 \times \frac{2}{1} \times 3$

= 6 days to get to the next pond.

When the snail crawls 1/3 of a mile per day, it will take him, $1 \times \frac{3}{1} \times 3$

= 9 days to get to the next pond.

When the snail crawls 1/4 of a mile per day, it will take him, $1 \times \frac{4}{1} \times 3$

= 12 days to get to the next pond.

When the snail crawls 3/4 of a mile per day, it will take him, $1 \times \frac{4}{3} \times 3$

= 4 days to get to the next pond.

When the snail crawls 2/3 of a mile per day, it will take him, $1 \times \frac{3}{2} \times 3$

= 4.5 days to get to the next pond.

3 0

3 years ago