A grade 2 class was playing guess my rule

Calculate the surface area of the cylinder.

Rainbow [258]

Method for SA of cylinder=
2 x pi x r x h + 2 x pi x r^2

SA = 2 x pi x 4 x 10 + 2 x pi x 4^2

= 351.9 cm^2

Hope this helps!!

7 0

3 years ago

4. An automobile dealership received 11 cars that needed to be detailed. If the

vova2212 [387]

Answer:

11 cars =21/2 hours

Convert 21/2 hours to minutes

60minutes =1hour

2.5 hours =150mins

11cars=150 mins

1 car =1/11×150mins=

150/11=13 7/11mins

7/11to seconds =60 seconds =1minutes

7/11×60secs =38secs

Answer =1car =13mins 38 secs

Step-by-step explanation:

8 0

3 years ago

What is the difference between theoretical and experimental probability

timama [110]

Theoretical probability is what we expect to happen, where experimental probability is what actually happens when we try it out. The probability is still calculated the same way, using the number of possible ways an outcome can occur divided by the total number of outcomes.

6 0

3 years ago

Read 2 more answers

15PTS QUICK

lana66690 [7]

Answer:

Option B

40x + 50y = 130

5x - 4y = 16

Option C

20x + 25y = 65

-20x + 16y = 64

Step-by-step explanation:

we have

$4x+5y=13$ ----> equation a

$10x-8y=-32$ ----> equation b

we know that

If two system of equations are equivalent, then their solution is the same

Part 1)

step 1

Multiply by 10 equation a both sides

$10(4x+5y)=10(13)$

$40x+50y=130$ ----> equation a'

step 2

Divide by 2 equation b both sides

$(1/2)(10x-8y)=(1/2)(-32)$

$5x-4y=-16$ ----> equation b'

so

The system of equations a and b and the system of equations a' and b' are equivalent

therefore

The system of equations a' and b' have the same solution as the given system

Part 2)

step 1

Multiply by 5 equation a both sides

$5(4x+5y)=5(13)$

$20x+25y=65$ ----> equation a'

step 2

Multiply by -2 equation b both sides

$-2(10x-8y)=-2(-32)$

$-20x+16y=64$ ----> equation b'

so

The system of equations a and b and the system of equations a' and b' are equivalent

therefore

The system of equations a' and b' have the same solution as the given system

6 0

3 years ago

Use an algebraic approach to solve the problem.

qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 = ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0

3 years ago