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schepotkina [342]
3 years ago
12

A grade 2 class was playing guess my rule

Mathematics
1 answer:
Setler [38]3 years ago
5 0
21-8=13 so hope that helps x
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PLEASE HELP!!<br> Find the area of the parallelogram.
pychu [463]
Base x height

So, 36 x 33
=1188
8 0
3 years ago
Find the value of x and the value of y.
jeka57 [31]

Answer:

x =  6/√3  ,   y = 12/√3

Step-by-step explanation:

sin 60° = opposite /hypothenus

√3/2 = 6/y

cross multiply

√3y=6 x 2 = 12

y = 12/√3

Tan 60° = opposite/adjacent

tan 60° = √3

√3 = 6/x

√3x= 6

x = 6/√3

7 0
3 years ago
Which table shows a proportional relationship between x and y?<br> Plz Help
Nastasia [14]

Answer:

The proportional table in the attached figure

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u><em>and the line passes through the origin</em></u>

<em>Verify each table</em>

Find the value of the constant of proportionality k for each ordered pair of a table.

k=\frac{y}{x}

If all the values of k are the same, then the table represent a proportional relationship between x and y

Table 1

For x=1, y=2 ----> k=\frac{2}{1}=2

For x=2, y=4 ----> k=\frac{4}{2}=2

For x=3, y=8 ----> k=\frac{8}{3}=2.7

The values of k are not equal

so

This table not represent a proportional relationship between x and y

Table 2

For x=0, y=4

The line not passes through the origin

so

This table not represent a proportional relationship between x and y

Table 3

For x=0, y=0 ----> is OK the line passes though the origin

For x=1, y=1 ----> k=\frac{1}{1}=1

For x=2, y=4 ----> k=\frac{4}{2}=2

The values of k are not equal

so

This table not represent a proportional relationship between x and y

Table 4

For x=1, y=4 ----> k=\frac{4}{1}=4

For x=2, y=8 ----> k=\frac{8}{2}=4

For x=3, y=12 ----> k=\frac{12}{3}=4

The values of k are the same

so

This table represent a proportional relationship between x and y

5 0
3 years ago
What is the exact area of a circular courtyard with a radius of 22 ft?
In-s [12.5K]
The answer is B 484pi ft squared
6 0
3 years ago
Read 2 more answers
(Will give Brainliest/5 Stars if correct answer)
tensa zangetsu [6.8K]
Answer: Choice D) 
The angle between the two vectors is approximately 71.6 degrees

----------------------------------------------
----------------------------------------------

Work Shown: 

Each time I write the word "dot" I mean "dot product". 

|u| = length of vector u
|u| = sqrt(u dot u)
|u| = sqrt(<8,4> dot <8,4>)
|u| = sqrt(8*8 + 4*4)
|u| = sqrt(64 + 16)
|u| = sqrt(80)
|u| = sqrt(16*5)
|u| = sqrt(16)*sqrt(5)
|u| = 4*sqrt(5)

-----------------------

|v| = length of vector v
|v| = sqrt(v dot v)
|v| = sqrt(<9,-9> dot <9,-9>)
|v| = sqrt(9*9 + (-9)*(-9))
|v| = sqrt(81+81)
|v| = sqrt(2*81)
|v| = sqrt(2)*sqrt(81)
|v| = sqrt(2)*9
|v| = 9*sqrt(2)

-----------------------

u dot v = <8,4> dot <9,-9>
u dot v = 8*9 + 4*(-9)
u dot v = 72-36
u dot v = 36

-----------------------

cos(theta) = (u dot v)/(|u|*|v|)
cos(theta) = (36)/(4*sqrt(5)*9*sqrt(2))
cos(theta) = (36)/(36*sqrt(10))
cos(theta) = 1/(sqrt(10))
cos(theta) = sqrt(10)/10
theta = arccos(sqrt(10)/10)
theta = 71.56505
which rounds to 71.6 when rounding to one decimal place (nearest tenth)

That's why the approximate answer is roughly 71.6 degrees

7 0
3 years ago
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