4 years ago

A grade 2 class was playing guess my rule

Mathematics

1 answer:

Setler [38]4 years ago

5 0

21-8=13 so hope that helps x

You might be interested in

Indicate the equation of the given line in standard form.

Minchanka [31]

wait do you want it in standard form

5 0

3 years ago

Read 2 more answers

Find the area of the two faces that make up the roof of the house.

MrRissso [65]

120+120=240
The roof of the house is 240 ft^2

7 0

3 years ago

11. A jug contains 2 gallons of water. How many quarts of water does the jug contain?

s2008m [1.1K]

Answer:

first change 1 gallon into quarts and that will be

4.8038

so 2 quarts = ? cross multiply ans the answer u will get is 9.6076

5 0

2 years ago

A roulette wheel has 38 slots around the rim. the first 36 slots are numbers from 1 to 36. half of these 36 slots are red, and

pshichka [43]

Answer:

15 or 16 times

Step-by-step explanation:

6 0

3 years ago

Choose one of the factors of 500x3 + 108y18

sammy [17]

Answer:

Option C

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

Step-by-step explanation:

Given: $500x^3 +108y^\left (18\right )$

the common factor from $500x^3$ and $108y^\left (18\right )$ is 4.

therefore, $4\cdot \left ( 125x^3+27y^\left (18\right ) \right )$

$4\cdot \left ( (5x)^3+(3y^6)^3 \right))$

Now, use the formula for above expression: $(a^3+b^3)=(a+b)(a^2-ab+b^2)$

here, $a=5x$ and $b=3y^6$

$( (5x)^3+(3y^6)^3 \right))$ $=(5x+3y^6)(25x^2-15xy^6+9y^12)$

Therefore, we have

$500x^3 +108y^\left (18\right )$ $=4\cdot (5x+3y^6)\left (25x^2-15xy^6+9y^\left ( 12 \right ) \right )$

Therefore, one of the factors of $500x^3 +108y^\left (18\right )$ is $(5x+3y^6)$ .

7 0

3 years ago

Read 2 more answers