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Inga [223]
2 years ago
6

Choose the most appropriate name for the function described below.

Mathematics
2 answers:
mina [271]2 years ago
7 0
I believe the answer is...C but I'm not entirely sure so i would wait for a second opinion : )


Andrei [34K]2 years ago
7 0

Answer:

Option C is correct

speed(memory) or s(m)

Step-by-step explanation:

Dependent variable states that  a variable whose value dependent upon the dependent variable.

For example: f(x)

x is the independent variable and f(x) is the dependent variable

Given the statement:

The speed of a computer depends on the amount of memory.

Let m represents the amount of memory and s represents the speed of a computer.

m = Independent variable

s(m) = Dependent variable on m

Then

the most appropriate name for the function described is:

speed(memory) or s(m)

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Evealute the expression when m= -2 m^2+9m+3
Volgvan

Step-by-step explanation:

m=-2

m^2+9m+3

substitute-2 in m

-2^2+9(-2)+3

= -19

8 0
2 years ago
Sorting through unsolicited e-mail and spam affects the productivity of office workers. An InsightExpress survey monitored offic
nydimaria [60]

Answer:

1. Refer to the explanation for the frequency table.

2. (a) 60%

   (b) 25%

Step-by-step explanation:

Part 1. The question is asking us to group the data according to the classes given and fill in the frequency (F), relative frequency (RF), cumulative frequency (CF) and relative cumulative frequency (RCF).

To compute the frequency for each class count the number of data that lies in the class range and write it. For the first class (1-5) we can see that there are 12 numbers which lie in the range 1 to 5. Those numbers are: 2, 4, 4, 1, 2, 1, 5, 5, 5, 3, 4, 4. Similarly, for the second class, the frequency is 3 because 8, 8, 8 lie in this range from our existing data. For the third class 11-15 there are 2 numbers in the given data which lie in this range and those numbers are 12, 15. Similarly, the rest of the frequencies can be computed.

For the relative frequency, the frequency of each class is divided by the total frequency i.e. 20.  

For the class 1-5, RF = 12/20 = 0.6.  

For 6-10, RF = 3/20 = 0.15

For 11-15, RF = 2/20 = 0.1

For 16-20, RF = 1/20 = 0.05

For 21-25, RF=1/20 = 0.05

For 26-30, RF = 0/20 = 0.00

For 31-34, RF= 1/20 = 0.05.

To compute the cumulative frequency, add the existing frequency of each class with the previous frequencies.

For 1-5, CF = 0+12 = 12

For 6-10, CF = 12+3=15

For 11-15, CF = 12+3+2 = 17

For 16-20, CF=12+3+2+1 = 18

For 21-25, CF = 12+3+2+1+1=19

For 25-30, CF = 12+3+2+1+1+0=19

For 31-34, CF = 12+3+2+1+1+0+1=20

Now, to compute relative cumulative frequency, add the existing relative frequency of each class with the previous relative frequencies.  

For 1-5, RCF = 0+0.6

For 6-10, RCF = 0.6 + 0.15 = 0.75

For 11-15, RCF = 0.6+0.15+0.1 = 0.85

The rest of the relative cumulative frequencies can be computed in the same way.

Class(Minutes)           F       RF     CF     RCF

      1-5                       12     0.60    12     0.60  

      6-10                      3     0.15     15     0.75  

      11-15                      2     0.10     17     0.85  

      16-20                    1      0.05    18     0.90  

      21-25                    1      0.05    19     0.95  

      26-30                   0     0.00    19     0.95  

      31-34                     1     0.05    20       1  

       <u>Total                  20</u>  

Part 2. Now, we are asked to compute the Ogive graph which is also called as the cumulative frequency graph. The cumulative frequency needs to be plotted on the y-axis and the upper limit of each class needs to be plotted on the x-axis. The graph is attached.

(a) From the graph we can see that the number of workers who spend less than 5 minutes on unsolicited e-mail and spam are 12. So the answer for this part is 12 workers.

Percentage = 12/20 x 100 = 60%

(b) From the graph we can see that the number of workers who spend less than 10 minutes on spam e-mail are 15. The question is asking for the number of people who spend more than 10 minutes. For this we need to subtract 15 from the total number of workers.  

Number of workers spending more than 10 minutes = 20-15 = 5 workers.

Percentage = 5/20 x 100 = 25%

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3 years ago
Solve for x.show your work please<br><br> - 1/2x &lt; -12
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Answer:

x <24

Step-by-step explanation:

first cancel negative signs

then transfer 2 to right side

3 0
3 years ago
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goblinko [34]
Solve x by simplifying both sides of the equation & then isolating the variable x=-4 & the negative comes in from the -12
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3 years ago
(2a² – b) (за² + 3b)
nataly862011 [7]

Answer:

a^4+3a^2-3b^2

Step-by-step explanation:

\hookrightarrow \: (2 {a}^{2}  - b)(3 {a}^{2}  + 3b) \\  \hookrightarrow \:2 {a}^{2} (3 {a}^{2}  + 3b) - b(3 {a}^{2}  + 3b) \\  \hookrightarrow \:6 {a}^{4}  + 6 {a}^{2} b - 3 {a}^{2} b - 3 {b}^{2} \\   \hookrightarrow \:{a}^{4}  + 3 {a}^{2} b- 3 {b}^{2}

6 0
2 years ago
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