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vredina [299]
3 years ago
13

(15points) Please help me with this bonus!! I really need help!!

Mathematics
2 answers:
jeka57 [31]3 years ago
7 0

Solve each equation separately:

(-1, 3) Has to be a point that fits both equations

y = 2x + ____

Plug in Values:

3 = 2(-1) + ____

3 = -2 + ____

___ = 5

First Blank: 5

y = ___x - 1

Plug in Values:

3 = ___(-1) - 1

4 = ___(-1)

___ = -4

Second Blank: -4

rodikova [14]3 years ago
3 0

the first one you plug in 3 for y and -1 for x:

3=2(-1)+? plug in x&y coordinates

3= -2 +? multiply -1×2

5 = ? add 2 to both sides

the second one you do the same:

3=?(-1)-1 plug in x&y coordinates

4=?(-1) add 1 to both sides

-4=? divide by -1

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Answer:

Case n =5

z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894  

Case n =15

z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549  

Case n = 40

z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530  

P value

Case n =5

p_v =P(z  

Case n =15

p_v =P(z  

Case n =40

p_v =P(z  

Step-by-step explanation:

Data given and notation  

\bar X=4.8 represent the sample mean

\sigma=0.5 represent the population standard deviation

n sample size  

\mu_o =5 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is lower than 5, the system of hypothesis would be:  

Null hypothesis:\mu \geq 5  

Alternative hypothesis:\mu < 5  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

Case n =5

z=\frac{4.8-5}{\frac{0.5}{\sqrt{5}}}=-0.894  

Case n =15

z=\frac{4.8-5}{\frac{0.5}{\sqrt{15}}}=-1.549  

Case n = 40

z=\frac{4.8-5}{\frac{0.5}{\sqrt{40}}}=-2.530  

P-value  

Since is a left tailed test the p value would be:  

Case n =5

p_v =P(z  

Case n =15

p_v =P(z  

Case n =40

p_v =P(z  

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Which table represents a direct variation? Table A x 4 6 8 10 y 7 9 11 13 Table B x 4 6 8 10 y 12 18 24 30 Table C x 4 6 8 10 y
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Answer:

We conclude that 'Table B' represents a direct variation.

Step-by-step explanation:

We know that when y varies directly with x, the equation is

y ∝ x

y = kx

k = y/x

where 'k' is called the constant of proportionality.

Table A

x     4 6 8 10

y     7 9 11 13

Finding k for all the pairs of x and y

k = y/x

k = 7/4, k = 9/6 = 3/2, k = 11 / 8, k = 13/11

As constant of proportionality 'k' does not remain constant.

Hence, table A does not represent a direct variation

Table B

x     4   6   8   10

y     12 18 24 30

Finding k all the pairs of x and y

k = y/x

k = 12/4 = 3, k = 18/6 = 3, k = 24/8 = 3, k = 30/10 = 3

As the constant of proportionality remains constant.

Therefore, the value of k = 3 for all the points in the table.

Hence, table B represents a direct variation.

Table C

x     4   6   8   10

y     1    3    5    7

Finding k all the pairs of x and y

k = y/x

k = 1/4, k = 3/6 = 1/2, k = 5/8, k = 7/10

As the constant of proportionality 'k' does not remain constant.

Hence, table C does not represent a direct variation.

Table D

x     4   6   8   10

y     3   3   3    3

Finding k all the pairs of x and y

k = y/x

k = 3/4, k = 3/6, k = 3/8, k = 3/10

As the constant of proportionality 'k' does not remain constant.

Hence, table D does not a direct variation.

Therefore, we conclude that 'Table B' represents a direct variation.

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3 years ago
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