Answer:
f+g(2)=10
f-g(4)=-4
F/G(2)= 7/3
(f)(g)(1)=0
Step-by-step explanation:
1. (f+g)=2x+3+x^2-1 2(2)+2=10
2. (f-g)=(2x+3)-(x^2-1)=-x^2+2x+4= -16+8+4=-4
3. f/g= 2x+3/x^2-1 4+3/3= 7/3
4. f*g= (2x+3)(x^2-1)= 2x^3+3x^2-2x-3= 2(1)^3-2(1)+3(1)^2-3=0
Answer:
Mmmm tricky but I'll try..
take away 4 apples from the basket with 9 and place it in the one with 1 apple
then take away one apple from the one with 6 and place it in the basket with 4
And now you have 5 apples in each basket
Happy now?
Are you missing information and or a picture that was provided?
<em>The point where a function (for our problem its the cubic function shown)</em>
<u>and/or</u>
<em>is a zero of the function.</em>
From the graph shown, we can clearly see that it cuts the x-axis at -1 and touches the x-axis at 2.
So the zeros are at -1 and 2.
ANSWER: {-1,2}
