Answer:
a= 158
b=22
Step-by-step explanation:
First we have to find b in order to find a.
To find b we need to add up the two angles we know the value of and subtract it from 180.
90+68= 158
180-158=22
We know b is 22 because the sum of all angles in a triangle is always 180.
Now that we have b we can find a.
we know that a+b=180 so all we have to do is subtract 22 from 180 to get 158.
Given:
Consider the expression are
1) 
2) ![\sqrt[3]{-8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D)
3) 
4) ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
To find:
The simplified form of each expression.
Solution:
1. We have,
Therefore, the value of this expression is 6.
2. We have,
![\sqrt[3]{-8}=(-8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28%28-2%29%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=(-2)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-2%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{-8}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D-2)
Therefore, the value of this expression is -2.
3. We have,
Therefore, the value of this expression is -10.
4. We have,
![\sqrt[3]{27}=(27)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%2827%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
Therefore, the value of this expression is 3.
Answer:
s=13
Step-by-step explanation:
Answer:
1.3 times 10 to the 25th power
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
