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Rasek [7]
3 years ago
7

Mario makes 6 free throw shots out of his first 10 attempts. What is the least number of consecutive shots Mario must make to in

crease his percentage from 60% to at least 70%?
Mathematics
2 answers:
alukav5142 [94]3 years ago
8 0
<h2>Answer:</h2>

The least number of consecutive shots Mario must make to increase his percentage from 60% to at least 70% is:

                                    4

<h2>Step-by-step explanation:</h2>

Mario makes 6 free throw shots out of his first 10 attempts.

The percentage is: 60%

  • Now if she make 1 more shot at the 11th attempt then the percentage will be:

\dfrac{7}{11}\times 100=63.63\%

( Since out of total 11 attempts she made 6 free throw before and 1 more at 11th attempt )

  • If she makes 2 consecutive shot after 10 attempts then the percentage will be:

             \dfrac{8}{12}\times 100=66.67\%

 Similarly,

  • If she makes 3 consecutive shot after 10 attempts then the percentage will be:

             \dfrac{9}{13}\times 100=69.231\%

                  which is still less than 70%

  • Now if she makes 4 consecutive attempts in the 4 throws after 10 attempts then,

               Percentage will be:

                 \dfrac{10}{14}\times 100=71.429\%

                Hence, the percentage is atleast 70%

Hence, he has to make 4 consecutive shots to increase his percentage to atleast 70%.

MArishka [77]3 years ago
3 0
4 consecutive shots will put him at 10-14 71.42%
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<h3>The dimensions of the given rectangular box are:</h3><h3>L  =   15.874 cm  , B  =  15.874 cm   , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box  

= Area of the base +  4 x ( Area of the adjacent faces)

=  S x S  +  4 ( S x H)   = S² +  4 SH   ..... (1)

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B  = 15.874 cm

H = 7.8937 cm

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