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3 years ago

What is equivalent to 8-8x

1 answer:

3 0

8 - 8x is already in its simplest form.

Without knowing the value of x, you cannot find what is equivalent to 8 - 8x, but you can it if is an equation, such as 8 - 8x = 88 (x would be -10).

However, you can still rewrite it as -8x + 8, which is equivalent to 8 - 8x.

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Help me pleaseeeee somebody ASAP

tatyana61 [14]

Answer:

x = 12

Step-by-step explanation:

In similarity triangles angles are congruent.

∠D = ∠A

x² - 8x = 48

x² - 8x - 48 = 0

x² + 4x - 12x - 48 = 0

x(x + 4) - 12(x + 4) = 0

(x +4)(x - 12) = 0

x - 12 = 0 {Ignore x + 4 = 0, as measurements won't have negative values}

x = 12

3 0

3 years ago

The Council of American Beet Farmers estimate that 60% of Americans love beets.

harkovskaia [24]

Answer: 13% or 0.1314

Step-by-step explanation: Binomial PDF on the calculator or by hand its

22 nCr 15 (0.60)^15(1-0.6)^7 = 0.131378

5 0

3 years ago

Plz help with equation of the circle will award fastest CORRECT answer with brainliest

aliina [53]

Answer:

$(x-1)^2+(y-2)^2=6.25$

Step-by-step explanation:

The equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the center and r is the radius.

The center is the red dot, which is (1,2). Thus, h=1 and k=2.

To find the radius, you need to use the distance formula. We are given two coordinates: the center (red dot) at (1,2) and a blue dot on the circle at (2.5,4). Find the radius by using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let (1,2) be x₁ and y₁ and let (2.5,4) be x₂ and y₂. Therefore:

$d=\sqrt{(2.5-1)^2+(4-2)^2}\\d=\sqrt{(1.5)^2+2^2}\\d=\sqrt{2.25+4}\\d=\sqrt{6.25}=2.5$

Thus, r is 2.5.

Plugging these numbers into the equation, we have:

$(x-h)^2+(y-k)^2=r^2\\(x-1)^2+(y-2)^2=2.5^2\\(x-1)^2+(y-2)^2=6.25$

3 0

3 years ago

On a finance exam, 15 accounting majors had an average grade of 90. On the same exam, 7 marketing majors averaged 85, and 10 fin

lilavasa [31]

Answer:

89.84375

Step-by-step explanation:

Given that on a finance exam, 15 accounting majors had an average grade of 90. On the same exam, 7 marketing majors averaged 85, and 10 finance majors averaged 93.

To find weighted mean.

Here weights can be considered as number of majors in each subject

$Marks x 90 85 93\\Weights 15 7 10\\Product 1350 595 930\\$