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Lyrx [107]
3 years ago
13

Use rounding or compatible numbers to estimate the sum

Mathematics
1 answer:
aliya0001 [1]3 years ago
8 0

Need more information please

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Assume you purchased a car for $2,300 and sold it one week later for $3,100. How much did your net worth change, if at all?
Natali5045456 [20]

Answer:

My net wroth would have changed by $800

Step-by-step explanation:

Because $3,100 - $2,300 = $800

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The first step to solve the equation x/4-3/4=16 is shown below
Sladkaya [172]

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i think it is A because that seems like the one making the most sense

Step-by-step explanation:

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3 years ago
What are the constants in the expression below? Check all that apply.
AlexFokin [52]
Constants are numbers alone with no variables.

The constants are: 12, -3.7, 1/3
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3 years ago
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7 0
2 years ago
How do you do this question?
alina1380 [7]

Answer:

(8√2) / 15

Step-by-step explanation:

A curve bounded by the y-axis is represented by in terms of dy;

\int \:x\:dt

When the curve crosses the y-axis, x will be 0. In this case x is the function of t, so we have to solve for x(t) = 0;

0 = t^2 + 2t --- (1)

Solution(s) => t = 0, t = 2

dy = (1/2 * 1/√t)dt --- (2)

Our solutions (0, 2) are our limits. The area of the curve is in the form A\:=\:\int _b^a\:f\left(t\right)g'\left(t\right)dt , so now let's introduce the limits of integration, x(t) and dy/dt. Remember, dy/dt = (1/2 * 1/√t) (second equation). 1/2 * 1/√t can be rewritten as 1/2 * t^(-1/2)....

A\:=\:\int _2^0\:\left(t^2-2t\right)\left(\frac{1}{2}t^{-\frac{1}{2}}\right)dt\\\\= \int _2^0\:\left(\frac{1}{2}t^{\frac{3}{2}}-t^{\frac{1}{2}}\right)dt\\\\= \left[\frac{t^{\frac{5}{2}}}{5}-\frac{2t^{\frac{3}{2}}}{3}\right]_2^0\\\\= 0\:-\:\left(\frac{4\sqrt{2}}{5}-\frac{4\sqrt{2}}{3}\right)\\\\= \frac{8\sqrt{2}}{15}

Your solution is 8√2 / 15

7 0
3 years ago
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