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Stells [14]
3 years ago
6

Find the measure of angle y. Round your answer to the nearest hundredth.

Mathematics
2 answers:
Irina-Kira [14]3 years ago
6 0

Answer:

20 degrees

Step-by-step explanation:

Hello

this is a right triangle, In a right triangle, the hypotenuse is the longest side, an "opposite" side is the one facing a given angle, and an "adjacent" side is next to a given angle.

Hence according to the graph

if "y" is the angle

opposite side = 5 units

adjacent side = 14 units

to find the value of "y" it is  possible to use the tangent fuction, wich is given by.

tan (y)=\frac{opposite\ side}{adjacent\ side} \\

replacing

tan (y)=\frac{5}{14}\\ to\ isolate\ y, do\ inverse\ tan\ in\ each\ side\\ tan^{-1} (tan(y))=tan^{-1}\frac{5}{14} \\ y=tan^{-1}(\frac{5}{14})\\

using a table or a calculator you can find this value

tan^{-1}(\frac{5}{14})=19.65\ degrees\\\\y=20\ degrees

Have a great day

Cloud [144]3 years ago
3 0

Answer:

<h2>y° = 20°</h2>

Step-by-step explanation:

Use tangent.

tangent=\dfrac{opposite}{adjacent}

We have

opposite=5\\adjacent=14

Substitute:

\tan y^o=\dfrac{5}{14}\\\\\tan y^o\approx0.3571\to y^o\approx20^o

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Given two vectors a⃗ =4.00i^+7.00j^ and b⃗ =5.00i^−2.00j^ , find the vector product a⃗ ×b⃗ (expressed in unit vectors). what is
FinnZ [79.3K]

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Further explanation:

Given:

Vector a is \vec a = 4.00\hat i + 7.00\hat j.

Vector b is \vec b = 5.00\hat i - 2.00\hat j.

Explanation:

The cross product of a \times b can be obtained as follows,

\begin{aligned}a \times b &= \left| {\begin{array}{*{20}{c}}{\hat i}&{\hat j}&{\hat k} \\4&7&0\\5&{ - 2}&0 \end{array}}\right|\\&= \hat i\left( {0 - 0} \right) - \hat j\left( {0 - 0} \right) + \hat k\left( { - 9 - 35} \right)\\&= 0\hat i - 0\hat j - 43\hat k\\&= - 43\hat k\\\end{aligned}

The vector can be expressed as follows,

a \times b =  - 43\hat k

The magnitude of a \times bcan be obtained as follows,

\begin{aligned}\left| {a \times b} \right| &= \sqrt {{0^2} + {0^2} + {{\left( { - 43} \right)}^2}}\\&= \sqrt {{{43}^2}}\\&= 43\\\end{aligned}43404

The vector product of \boxed{a \times b =  - 43\hat k} and the magnitude of a \times b is \boxed{43}.

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Vectors

Keywords: two vectors, vector product, expressed in unit vectors, magnitude, vector a, vector b, a=4.00i^+7.00j^, b=5.00i^-2.00j^, unit vectors, vector space.

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