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4 years ago

Help please ASAP thx all of them

Mathematics

1 answer:

Radda [10]4 years ago

6 0

Hi, these equations are pretty easy actually, first thing you should know when working with variables is that you always want to leave the variable alone, let's take the third excersise for example, 12x + 2 = 146. Here you just do the opposite on the other side of the equation depending if the number is positive or negative. Since x is being multiplied by 12 you first get rid of the 2, since its positive you subtract it to 146. Now the answer should be 12x = 144. Now since you're multiplying 12 to x you just divide 12 from 144, 144/12 = 12
x = 12

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The ratio of the measures of the three sides of a triangle is 1/4:1/3:1/6 and its perimeter is 31.4 centimetres find the length

lina2011 [118]

Given:

The ratio of the measures of the three sides of a triangle is $\dfrac{1}{4}:\dfrac{1}{3}:\dfrac{1}{6}$ .

Its perimeter is 31.4 centimeters

To find:

The shortest side of the triangle.

Solution:

Let the measures of the three sides of a triangle are $\dfrac{1}{4}x,\dfrac{1}{3}x,\dfrac{1}{6}x$ respectively (in cm).

Its perimeter is 31.4 centimeters.

$\dfrac{1}{4}x+\dfrac{1}{3}x+\dfrac{1}{6}x=31.4$

$\dfrac{3x+4x+2x}{12}=31.4$

$\dfrac{9x}{12}=31.4$

$\dfrac{3x}{4}=31.4$

On further simplification, we get

$3x=4\times 31.4$

$3x=125.6$

Divide both sides by 3.

$x=\dfrac{125.6}{3}$

$x=41.867$

Now, the sides of triangle are

$\dfrac{1}{4}(41.867)=10.467$

$\dfrac{1}{3}(41.867)=13.956$

$\dfrac{1}{6}(41.867)=6.978$

Therefore, the length of the shortest side is 6.978 cm.

5 0

3 years ago

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slega [8]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

The 11th term of an progression is 25 and the sum of the first 4 terms is 49. The nth term of the progression is 49

KIM [24]

Answer:

For 1: The first term is 10 and the common difference is $\frac{3}{2}$

For 2: The value of n is 27

Step-by-step explanation:

The n-th term of the progression is given as:

$a_n=a_1+(n-1)d$

where,

$a_1$ is the first term, n is the number of terms and d is the common difference

The sum of n-th terms of the progression is given as:

$S_n=\frac{n}{2}[2a_1+(n-1)d]$

where,

$S_n$ is the sum of nth terms

For (1):

The 11th term of the progression:

$25=a_1+10d$ .......(1)

Sum of first 4 numbers:

$49=\frac{4}{2}[2a_1+3d$ ......(2)

Forming equations:

$98=8a_1+12d$

$25=a_1+10d$ ( × 8)

The equations become:

$98=8a_1+12d$

$200=8a_1+80d$

Solving above equations, we get:

$102=68d\\\\d=\frac{102}{68}=\frac{3}{2}$

Putting value in equation (1):

$25=a_1+10\frac{3}{2}\\\\a_1=[25-15]=10$

Hence, the first term is 10 and the common difference is $\frac{3}{2}$

For 2:

The nth term is given as:

$49=10+(n-1)\frac{3}{2}$

Solving the above equation:

$39=(n-1)\frac{3}{2}\\\\n-1=26\\\\n=27$

Hence, the value of n is 27

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3 years ago

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Korolek [52]

Answer:

106

Step-by-step explanation:

angle c = 180-74 = 106

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3 years ago

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Triangle PQR is similar to triangle XYZ. What is the perimeter of triangle XYZ?

xeze [42]

Triangle PQR is similar to triangle XYZ. What is the perimeter of triangle XYZ? Where is the picture

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3 years ago