Equality d is true, the others aren't.
Answer:
<u>Given :</u>
length offshore = CS=√(1+X^2)
Cable charged = 5000√(1+X^2)
onshore length = 4-X
laying cost = 3000(4-X)
total cost:
C=5000√(1+X^2) +3000(4-X)
DC/DX
= [5000*(0.5)*2X/{√(1+X^2)}]-3000=0... for optimum
5000X=3000√(1+X^2)
25X^2=3+3X^2
22X^2=3
X=√(3/22)
= 0.3693 miles
So, it would be laid offshore to S in a manner that
BS=X=0.3693 miles
Onshore=4-0.3693
=3.6307 miles
Answer:
√65 ft = 8.1 ft
Step-by-step explanation:
We solve using Pythagoras Theorem
c² = a² + b²
c = √a² + b²
Where c = Length of the Hypotenuse
a = 4ft , b = 7ft
Hence
c = √4² + 7²
c = √16 + 49
c = √(65)
c = 8.0622577483 ft
Approximately = 8.1 ft
Therefore, the length of the hypotenuse is √65 ft = 8.1 ft
Answer:
1/2=(A+B)
area of triangle=1/2×base×height
