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Anton [14]
3 years ago
10

QUESTION 2

Mathematics
1 answer:
Makovka662 [10]3 years ago
6 0

Answer:

10/8+10.62

23*8*10.62

10.62*8+23

23+8*10.62

Step-by-step explanation:

Either one of these, I hope this helps:)

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What is the value of m in the equation 5m − 7 = 6m + 11? ((99) points!! Give me you number? Maybe?)
kolbaska11 [484]

5m-7=6m+11

We want to isolate "m" on one side of the equation and have a number on the other side. Let's start by subtracting both sides by 5m

5m-7-5m=6m+11-5m

-7=m+11

Now, let's subtract both sides by 11

-7-11=m+11-11

-18=m

We now have the value of m.

The next thing I'm going to do is a bit tedious, but you typically want to have the variable on the left side of the equation in the field of math. It's a good habit to develop now.

m=-18

Thus, the answer is choice 3, -18. Let me know if you need any clarifications, thanks!

~ Padoru

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3 years ago
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How do I solve 9x-4= -44​
gulaghasi [49]
9x - 4 = -44
•add 4 to both sides to isolate the variable
9x = -40
•divide both sides by 9 to isolate the variable
x = -40/9 or −4.444...
6 0
3 years ago
When given a raw score, explain how to use the normal curve to compare that score to the population.
damaskus [11]

Assuming you know the mean (mu) and the standard deviation (sigma), you would use the raw score (x) to get the z score through this formula

z = (x-mu)/sigma

If you get a positive z value, then the raw score is above the mean. If z is negative, then the raw score is below the mean.

The absolute value of z tells us how far away from the mean we are in terms of standard deviation.

Eg: z = -3 leads to |z| = |-3| = 3, so we're 3 standard deviations below the mean.

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3 years ago
The vertical angle to the top of a flagpole from point A on the ground is observed to be 37°11'. The observer walks 17 m directl
inysia [295]

Answer:

22m

Step-by-step explanation:

Let height of flagpole=h

AB==17 m

\angle CAD=37^{\circ}11'=37+\frac{11}{60}=37.183^{\circ}(1 degree= 60 minute)

\angle B=25^{\circ}43'=25+\frac{43}{60}=25.72^{\circ}

We have to find the approximate height of the flagpole.

In triangle CDA,

\frac{CD}{DA}=tan\theta=\frac{Perpendicular\;side}{Base}

\frac{h}{DA}=tan37.183^{\circ}

h=DA(0.759)

In triangle CDB,

tan 25.72^{\circ}=\frac{CD}{DB}

0.482=\frac{h}{DA+17}

0.482DA+8.194=h

Substitute the value

0.482DA+8.194=0.759DA

8.194=0.759DA-0.482DA

8.194=0.277DA

DA=\frac{8.194}{0.277}=29.58

Substitute the value

h=29.58 \times 0.759=22.45 m\approx 22m

Hence, the height of the flagpole=22 m

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3 years ago
Cassidy says that the capacity is the same as the amount. Do you agree explain why or why not.
Zinaida [17]
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4 years ago
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