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Zanzabum
3 years ago
11

Helppppp me pleaseeeee

Mathematics
2 answers:
inessss [21]3 years ago
7 0
The unknown digit is 1
5024/16= 314
Andreyy893 years ago
5 0

Answer:

314- The unknown digit is 1

Step-by-step explanation:

16*314=5024

5024/16=314

Hope this helps ;) ❤❤❤

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Use the balanced scale to find the conversion factor that can be used to convert the number of blocks to the weight of the block
marusya05 [52]

Answer:

the answer is 24 lb

i think

Stepkby-step explanation:

it is 24 because it is 6 1lb blocks x 4 will give you 24

4 0
3 years ago
Read 2 more answers
A paint store sells exterior paint for $35.75 a gallon and paint rollers for $6.00 each. Write an equation in standard form for
VLD [36.1K]
The total price for the gallons of paint will be 35.75p

The total price for the rollers will be 6r

So the equation if the customer have 190 will be
price for gallons of paint + price for rollers = 190
35.75p + 6r = 190
<em>(This is the equation)</em>
3 0
3 years ago
Princess bought 7 bracelets that each cost the same amount and pair of earrings that costs $15. The items she bought cost a tota
vladimir2022 [97]

Answer:

Step-by-step explanation:

Your gonna subtract the cost of the pair earrings from the total. 260-15=245, then you will divide 245 by 7. 245/7=35. So each bracelet cost's 35 each.

8 0
3 years ago
During an Apollo moon landing, reflecting panels were placed on the moon. This allowed Earth-based astronomers to shoot laser be
rusak2 [61]

Answer:

The distance between the astronomers and the moon was 7.56*10^{8] meters.

Step-by-step explanation:

We have that the speed is the distance divided by the time, so:

v = \frac{d}{t}

In this problem, we have that:

The reflected laser beam was observed by the astronomers 2.52 s after the laser pulse was sent. This means that t = 2.52.

If the speed of light is 3.00 times 10^8 m/s, what was the distance between the astronomers and the moon?

We have that v = 3*10^{8}m/s.

We have to find d. So:

v = \frac{d}{t}

d = vt

d = 3*10^{8}*2.52

7.56*10^{8]

The distance between the astronomers and the moon was 7.56*10^{8] meters.

7 0
3 years ago
Help me out please an thank you
fomenos

Answer:

Eg would be 10.6 because its the same length as EF

7 0
3 years ago
Read 2 more answers
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