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2 answers:
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Given:
A line passes through (1,-2) and is perpendicular to .
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
0.51 cm
Step-by-step explanation:
In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°
By the sine definition,
Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,
In the right triangle, two acute angles are always complementary, so
Thus,
Answer:
- g(x) = 2|x|
- g(x) = -2|x|
- g(x) = -2|x| -3
- g(x) = -2|x-1| -3
Step-by-step explanation:
1) Vertical stretch is accomplished by multiplying the function value by the stretch factor. When |x| is stretched by a factor of 2, the stretched function is ...
g(x) = 2|x|
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2) Reflection over the x-axis means each y-value is replaced by its opposite. This is accomplished by multiplying the function value by -1.
g(x) = -2|x|
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3) As you know from when you plot a point on a graph, shifting it down 3 units subtracts 3 from the y-value.
g(x) = -2|x| -3
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4) A right-shift by k units means the argument of the function is replaced by x-k. We want a right shift of 1 unit, so ...
g(x) = -2|x -1| -3
