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Jet001 [13]
3 years ago
8

This course will emphasize the use of math concepts solve real world problems.

Mathematics
1 answer:
liraira [26]3 years ago
3 0

True! we use math everyday in the real world and sometimes you dont even realize

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If the interest is compounded continuously, what interest rate do you need for a 5000 investment to double in 10 years
velikii [3]

Answer:

rate = natural log (Total / Principal) / Years

We need 5,000 to become 10,000 in 10 years so,

rate = natural log (Total / Principal) / Years

rate = natural log(10,000 / 5,000) / 10

rate = natural log(2) / 10

rate = 0.69314718056 / 10

rate = .069314718056 which equals

rate = 6.9314718056 per cent

Source: https://www.1728.org/rate2.htm

(scroll to the bottom)

Step-by-step explanation:

5 0
3 years ago
41. Suppose a family drives at an average rate of 60 mi/h on the way to visit relatives and then at an average rate of 40 mi/h o
Afina-wow [57]

Answer:

The answer is below

Step-by-step explanation:

a) Let x represent the time taken to drive to see the relatives and let d be the distance travelled to go, hence:

60 mi/h = d/x

d = 60x

When returning, they still travelled a distance d, since the return trip takes 1 h longer than the trip there, therefore:

40 mi/h = d/(x+1)

d = 40(x + 1) = 40x + 40

Equating both equations:

60x = 40x + 40

60x - 40x = 40

20x = 40

x = 40/20

x = 2 h

The time taken to drive there = x = 2 hours

b) The time taken for return trip = x + 1 = 2 + 1 = 3 hours

c) The distance d = 60x = 60(2) = 120 miles

The total distance to and fro = 2d = 2(120) = 240 miles

The total time to and fro = 2 h + 3 h = 5 h

Average speed = total distance / total time = 240 miles / 5 h = 48 mi/h

5 0
3 years ago
Which unit of measure is best for measuring how much a bicycle weighs
Kazeer [188]
I would say A scale which measures by pounds
7 0
3 years ago
Please help!!!!! ASAP!!!
nika2105 [10]
That's just the distance between 2 points
the distance between (x1,y1) and (x2,y2) is
D= \sqrt{(x2-x1)^2+(y2-y1)^2}

we can find the distance between S and Q or P and R

S and Q is (0,0) and (a,b)

D= \sqrt{(a-0)^2+(b-0)^2}
D= \sqrt{a^2+b^2}

distance between P and R is between(0,b) and (a,0)
D= \sqrt{(a-0)^2+(0-b)^2}
D= \sqrt{(a)^2+(-b)^2}
D= \sqrt{a^2+b^2}

\sqrt{a^2+b^2} = \sqrt{a^2+b^2}
so the lengths of diagonals are congruent
7 0
4 years ago
Solve the equation 8x-7=y-2 for x if y is 51. make sure to first solve for in terms y. x=?
Crank
X=7. if you need explanation message me
7 0
3 years ago
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