Question

Find BC, Round to the nearest tenth

Answer 1

Given:

Given that the measure of ∠A is 74°

The length of side b is b = 6.

The length of side c is c = 5.

The length of side BC is a.

We need to determine the value of BC.

Value of BC:

The value of BC can be determined using the law of cosine formula.

Thus, we have;

$a^2=b^2+c^2-2bc \ cos (A)$

Substituting b = 6, c = 5 and ∠A = 74°, we get;

$a^2=6^2+5^2-2(6)(5) \ cos \ 74^{\circ}$

$a^2=36+25-2(30)(0.28)$

$a^2=36+25-16.8$

$a^2=44.2$

 $a=6.6$

Thus, the length of BC is 6.6 units.