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3 years ago

How many eighth-size parts do you need to model 3/4? explain

1 answer:

8 0

The way I understand this question is: "how many of one eights (1/8) can fit into 3/4 - so mathematically we would write: 3/4 divided by 1/8. Dividing by a fraction is multiplying by its inverse, so we have 3/4 multiplied by 8, which is 3*8/4, we simplify by dividing 8 and 4 by 4: 6/1, that is 6 - the answer is 6!Hope this helps. Let me know if you need additional help!

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Abc is a right angled triangle. if b= 90°, ac = 96cm c= 30°

zysi [14]

Answer:

sorry for the late answer

8 0

3 years ago

You receive two quarters, one dime, and four pennies back in change. Write the amount as a fraction in simplest form

Ahat [919]

$\frac{50}{100} = \frac{2}{4} = \frac{1}{2}$
$\frac{10}{100} = \frac{1}{10}$
$\frac{4}{100} = \frac{2}{50} = \frac{1}{25}$
$\frac{1}{2} = .50$
$\frac{1}{25} = .04$
$\frac{1}{10} = .10$

7 0

3 years ago

Read 2 more answers

Solve for x pls show work 1/2*(x - -6)= -1

Pavlova-9 [17]

Answer: x = -4

Step-by-step explanation:

1/2 * (x - (-6)) = 1

distribute

1/2x + 3 = 1

isolate the variable

1/2x = -2

x = - 4

5 0

3 years ago

⦁ In a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football. Construct a 95% confiden

fomenos

Answer:

95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

Step-by-step explanation:

We are given that in a simple random sample of 1219 US adults, 354 said that their favorite sport to watch is football.

Firstly, the pivotal quantity for 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = proportion of adults in the United States whose favorite sport to watch is football in a sample of 1219 adults = $\frac{354}{1219}$

n = sample of US adults = 1291

p = population proportion of adults

Here for constructing 95% confidence interval we have used One-sample z proportion statistics.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

significance level are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]

= [ $\frac{354}{1219}-1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ , $\frac{354}{1219}+1.96 \times {\sqrt{\frac{\frac{354}{1219}(1-\frac{354}{1219})}{1219} }$ ]

= [0.265 , 0.316]

Therefore, 95% confidence interval for the proportion of adults in the United States whose favorite sport to watch is football is [0.265 , 0.316].

5 0

3 years ago

Please solve thank you

Y_Kistochka [10]

9514 1404 393

Answer:

Step-by-step explanation:

The second step of the solution shows division by 2 on the left. Consequently, it must also show division by 2 on the right.

2 goes in the green box

_____

$\dfrac{2p}{2}=\dfrac{18}{2}\\\\p=9$

7 0

3 years ago