Answer:
a
Step-by-step explanation:
Length (L): 2w + 3
width (w): w
border (b): 
Area (A) = (L + b) * (w + b) <em>NOTE: This is assuming the width also has a border</em>
= (2w + 3 +
) * (w +
)
= 

= 

= 
Where’s the problem where it explains what’s she is subtracting?
now, there are 12 months in a year, so 18 months is really 18/12 of a year, thus
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$4000\\ P=\textit{original amount deposited}\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ t=years\to \frac{18}{12}\dotfill &\frac{3}{2} \end{cases} \\\\\\ 4000=P[1+(0.05)(\frac{3}{2})]\implies 4000=P(1.075) \\\\\\ \cfrac{4000}{1.075}=P\implies 3720.93\approx P](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5Cdotfill%20%26%20%5C%244000%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%20r%3Drate%5Cto%205%5C%25%5Cto%20%5Cfrac%7B5%7D%7B100%7D%5Cdotfill%20%260.05%5C%5C%20t%3Dyears%5Cto%20%5Cfrac%7B18%7D%7B12%7D%5Cdotfill%20%26%5Cfrac%7B3%7D%7B2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%204000%3DP%5B1%2B%280.05%29%28%5Cfrac%7B3%7D%7B2%7D%29%5D%5Cimplies%204000%3DP%281.075%29%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B4000%7D%7B1.075%7D%3DP%5Cimplies%203720.93%5Capprox%20P)
Wow...we have lots of numbers to go through. we know that a 6 sided figure is a hexagon and the interior angles add up to be 720°. so.....
∠A + ∠B + ∠ C + ∠D + ∠E + ∠F = 720°
(x - 60) + (x - 40) + 130 + 120 + 110 + (x - 20) = 720
3x + 240 = 720 (combined all like terms)
3x = 480 (subtracted 240 from both sides)
x = 160 (divided both sides by 3)
put the value of x into ∠A (x - 60) = 160 - 60 = 100
∠A = 100°