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4 years ago

Algebra question please help me

Mathematics

2 answers:

Mila [183]4 years ago

7 0

What’s your question?

aliya0001 [1]4 years ago

4 0

Absolute value is defined as follows:

|x| = x if x ≥ 0 and -x if x < 0.

To make an equation using absolute value, you need to look for the following:

1) something where you use positive and negative numbers

2) something where changing the sign between positive and negative, or vice versa, doesn't affect the problem.

Choice A talks about price per gallons. You can't have negative money amounts so this one won't work.

Choice B talks about distances of walking. In math classes you can have negative distance, but not in reality. Nope.

Choice D talks about books. But books sold as a negative number means you bought them, and the meaning changes. Nope.

Choice C uses "plus or minus". It also talks about something that's approximate, and it's also a case where the signs won't matter. Bingo.

Thus choice C is best.

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Suppose on a certain test, fifty students earn a perfect score and fifty students earn a zero. determine the mean grade and stan

kodGreya [7K]

Answer:

Mean=50.

standard deviation=50.

Step-by-step explanation:

Let the perfect score be 100.

The mean(average) of a data is given by: $Mean=\frac{sum of data points}{number of data points}$

Here the number of data points are 100. out of which 50 attains a value 100,and 50 attains value 0.

so, sum of data points=50×100+50×0=5000.

$Mean=\frac{5000}{100}$

Mean=50.

"Now the standard deviation of data points are calculated by firstly subtracting mean from every entry and then square the number and take it as new entry and calculate the mean of the new data entry and lastly taking the square root of this new mean".

Here if 50 is subtracted from each entry the new entry will have 50 entries as '50' and 50 entries as '-50'.

next on squaring we will have all the 100 entries as '2500'.

now the mean of these entries is: $\frac{2500\times100}{100}$

=2500

taking it's squareroot we have $\sqrt{2500}=50$

Hence, standard deviation=50.

5 0

4 years ago

Read 2 more answers

In a certain population of mussels (Mytilus edulis), 80% of the individuals are infected with an intestinal parasite. A marine b

kirza4 [7]

Answer:

The probability that 85% or more of the sampled mussels will be infected is 0.1057.

Step-by-step explanation:

Let <em>X</em> = number of mussels infected with an intestinal parasite.

The probability that a random selected mussel is infected with an intestinal parasite is, <em>p</em> = 0.80.

A random sample of <em>n</em> = 100 mussels from the population are examined by a marine biologist.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 100 and p = 0.80.

But the sample selected is too large, i.e. <em>n</em> = 100 > 30.

So a Normal approximation to binomial can be applied to approximate the distribution of $\hat p$ <em>, </em>the sample proportion of mussels infected with an intestinal parasite, if the following conditions are satisfied:

np ≥ 10
n(1 - p) ≥ 10

Check the conditions as follows:

n × p = 100 × 0.80 = 80 > 10

n × (1 - p) = 100 × (1 - 0.80) = 20 > 10

Thus, a Normal approximation to binomial can be applied.

So, the distribution of $\hat p$ is:

$\hat p\sim N(p, \frac{p(1-p)}{n} )$

Compute the probability that 85% or more of the sampled mussels will be infected as follows:

Apply continuity correction:

$P(\hat p\geq 0.85)=P(\hat p>0.85+0.50)$

$=P(\hat p>0.90)\\$

$=P(\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}>\frac{0.85-0.80}{\sqrt{\frac{0.80(1-0.80)}{100}}})$

$=P(Z>1.25)\\=1-P(Z$

*Use a <em>z</em>-table for the probability.

Thus, the probability that 85% or more of the sampled mussels will be infected is 0.1057.

5 0

3 years ago

A box contains orange balls and green balls. The number of green balls is six more than four times the number of orange balls. I

Delvig [45]

This is your answer

3 0

3 years ago

4.4 = − t/4.5 solve for t

krek1111 [17]

Answer:

t= -19.8

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP ME OUT!!

Zielflug [23.3K]

Answer:

(d) 1/√(s³)

Step-by-step explanation:

The expression can be simplified by making use of the rules of exponents.

<h3>Rules of exponents</h3>

The relevant rules are ...

$a^b\cdot a^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\\left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}\\\\a^{b/c}=\sqrt[c]{a^b}$

<h3>Application</h3>

The given expression can be simplified by applying these rules.

$\left(\dfrac{1}{s^{-1}\cdot s^8}\right)^{3/14}=\dfrac{1}{(s^{-1+8})^{3/14}}=\dfrac{1}{s^{7\cdot3/14}}=\dfrac{1}{s^{3/2}}=\boxed{\dfrac{1}{\sqrt{s^3}}}$

3 0

2 years ago