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Sophie [7]
2 years ago
10

The property taxes on a house were $600. What was the tax rate if the house was valued at $100,000? Follow the problem solving a

nd round your answer to the nearest hundredth of a percent, if necessary.
Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
3 0

Based on the information given the tax rate if the house was valued at $100,000 is 60%.

Let $600= x%

Let $100,000=100%

Let the tax rate=x

Proportion:

600/100,000=x/100

Hence,

x=600×100/100,000

x=60,000/100,000

x=60/100

x=0.6%×100

x=60%

Inconclusion  the tax rate if the house was valued at $100,000 is 60%.

Learn more about tax rate here:brainly.com/question/9437038

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
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Step-by-step explanation:

Given that:

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Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

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\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

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\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

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= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

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Answer:

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