.736 rounded to the nearest tenth

1. The most massive planet in the solar system, Jupiter, has a mass of about 1,898,000,000,000,000,000,000,000,000 kg. Estimate

UNO [17]

Answer:

D. $2*10^{27} kg$

Step-by-step explanation:

Mass of Jupiter is given as 1,898,000,000,000,000,000,000,000,000 kg

Estimating this to the nearest whole number would be = 2,000,000,000,000,000,000,000,000,000 kg (rounding up the the "1,898")

To express this in scientific notation form, simply count how many zeros we have to the nearest whole number, 2.

We have 27 zeros there.

Therefore, we would multiply the whole number, 2, by 10 raise to the power of 27.

An estimate of the mass of Jupiter = $2*10^{27} kg$

6 0

3 years ago

52% of what number equals 39

OverLord2011 [107]

To figure this equation out, you'll have to divide 39 by 52% (0,52)

39 / 0.52 = 75

39 is 52% of 75 is your answer.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Abel saved 43 more nickels than dimes. After he spent 17 dimes he had twice as many nickels than dimes. How many coins did he ha

Alborosie

Answer:

180 coins

Explanation:

N = number of nickels (no nickels spent)

D = number of dimes initially saved

D' = number of dimes left after spending

1) N = D + 43

2) D' = D - 17

3) N = 2*D' = 2*(D - 17)

Set equations 1) and 3) equal to each other and solve for D:

D + 43 = 2*(D - 17)

D + 43 = 2*D - 34

D = 43 + 34 = 77

N = D + 43 = 77 + 43 = 120 nickels left

D' = D - 17 = 77 - 17 = 60 dimes left

Total coins left = 120 + 60 = 180 coins (I hope this is not too confusing for you)

8 0

2 years ago

A certain bay with very high tides displays the following behavior. In one 12-h period the water starts at mean sea level, rises

Firdavs [7]

Answer:

the required equation is; y = 21 sin(πt/6)

Step-by-step explanation:

Given the data in the question;

Water rises above sea level = 21 ft

Water drops below sea level = 21 ft

so

maximum = 21 ft and also

minimum = 21 ft

Amplitude = ( maximum + minimum ) / 2

Amplitude = ( 21 + 21 ) / 2

Amplitude = ( 21 + 21 ) / 2 = 42/2 = 21 ft

Period = 12 hours

and we know that; period = 2π/b

so

12 = 2π/b

12b = 2π

b = 2π / 12

b = π/6

Standard equation for simple harmonic is; y = asin(bt)

we substitute

y = 21 sin(πt/6)

Hence the required equation is; y = 21 sin(πt/6)

7 0

3 years ago

Please help me on this problem

Anna71 [15]

Answer:

The pairs of integer having two real solution for $ax^{2} -6x+c = 0$ are

$a = -4, c = 5$
$a = 1, c = 6$
$a = 2, c = 3$
$a = 3, c = 3$

Step-by-step explanation:

Given

$ax^{2} -6x+c = 0$

Now we will solve the equation by putting all the 6 pairs so we get the following

$-3x^{2} -6x-5 = 0$ for $a = -3 , c=-5$

$-4x^{2} -6x+5 = 0$ for $a = -4 , c=5$

$1x^{2} -6x+6 = 0$ for $a = 1 , c=6$

$2x^{2} -6x+3 = 0$ for $a = 2 , c=3$

$3x^{2} -6x+3 = 0$ for $a = 3 , c=3$

$5x^{2} -6x+4 = 0$ for $a = 5 , c=4$

The above all are Quadratic equations inn general form $ax^{2} +bx+c=0$

where we have a,b and c constant values

So for a real Solution we must have

$Disciminant , b^{2} -4\timesa\timesc \geq 0$

for $a = -3 , c=-5$ we have

$Discriminant =-24$ which is less than 0 ∴ not a real solution.

for $a = -4 , c=5$ we have

$Discriminant = 116$ which is greater than 0 ∴ a real solution.

for $a = 1 , c=6$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 2 , c=3$ we have

$Discriminant =12$ which is greater than 0 ∴ a real solution.

for $a = 3 , c=3$ we have

$Discriminant =0$ which is equal to 0 ∴ a real solution.

for $a = 5 , c=4$ we have

$Discriminant =-44$ which is less than 0 ∴ not a real solution.

7 0

3 years ago