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2 years ago

10

Plz help me well mark brainliest if correct ..........???

2 answers:

Fudgin [204]2 years ago

5 0

Answer: Mushrooms

Step-by-step explanation: Mushrooms are decomposers

yan [13]2 years ago

3 0

the correct answer is C. mushrooms give me a crown please

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Determine the equation for the given line in

Tema [17]

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Y= -3/5 - 1

Step-by-step explanation:

if you start on the y intercept an go down once (-1)

then go down three times (-3)

positive 5 so go right 5 times it lands on the point :)

im not a teacher and i took this last year so sorry if my explanation isn't the best

6 0

2 years ago

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Evaluate -15a (-3) for a= 2 and b=-3<br> A.) 5/24 B.) -5/24 C.) -1080 D.) -40/3

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Hhjhhhu did I need ooo 40

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3 years ago

Tony’s deposit earned $40.80 in simple interest over 3 years in an account with an interest rate of 1.7%. How much did Tony depo

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3. Tony's deposit earned $40.80 in simple interest over 3 years in an account with an interest rate of 1.7%. How much did Tony deposit?

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2 years ago

1. Divide using long division: (5x +13x² – 8x - 2) / (x+3)

DaniilM [7]

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6 0

3 years ago

The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?

omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

$T_5 = 160$

$T_7 = 40$

Required

$T_6$

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

$\frac{T_7}{T_5} = \frac{40}{160}$

Divide the numerator and the denominator of the fraction by 40

$\frac{T_7}{T_5} = \frac{1}{4}$ ----- equation 1

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Where n is the nth term

So,

$T_7 = a r^{6}$

$T_5 = a r^{4}$

Substitute the above expression in equation 1

$\frac{T_7}{T_5} = \frac{1}{4}$ becomes

$\frac{ar^6}{ar^4} = \frac{1}{4}$

$r^2 = \frac{1}{4}$

Square root both sides

$r = \sqrt{\frac{1}{4}}$

r = ± $\frac{1}{2}$

Next, is to solve for the first term;

Using $T_5 = a r^{4}$

By substituting 160 for T5 and ± $\frac{1}{2}$ for r;

We get

$160 = a \frac{1}{2}^{4}$

$160 = a \frac{1}{16}$

Multiply through by 16

$16 * 160 = a \frac{1}{16} * 16$

$16 * 160 = a$

$2560 = a$

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

$T_n = a r^{n-1}$

Here, n = 6;

$T_6 = a r^{6-1}$

$T_6 = a r^5$

$T_6 = 2560 r^5$

r = ± $\frac{1}{2}$

So,

$T_6 = 2560( \frac{1}{2}^5)$ or $T_6 = 2560( \frac{-1}{2}^5)$

$T_6 = 2560( \frac{1}{32})$ or $T_6 = 2560( \frac{-1}{32})$

$T_6 = 80$ or $T_6 = -80$

$T_6 =$ ±80

Hence, the 6th term is positive/negative 80

8 0

2 years ago