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3 years ago

2. 8x - 20y - 10 What are the coefficients

Mathematics

1 answer:

Finger [1]3 years ago

6 0

Answer:

8x and -20y

Step-by-step explanation:

any number that contains a variable is a coefficient.

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Which expressions are equivalent to \dfrac{4^{-3}}{4^{-1}} 4 −1 4 −3 start fraction, 4, start superscript, minus, 3, end super

Slav-nsk [51]

Answer:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

Step-by-step explanation:

Given

$\dfrac{4^{-3}}{4^{-1}}$

Required

Choose equivalent expressions

Choosing the first answer:

$\dfrac{4^{-3}}{4^{-1}}$

Split expressions

$4^{-3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{4^{-1}}$

Apply laws of indices: $(a^{-b} = \frac{1}{a^b})$

$\frac{1}{4^3} * \frac{1}{1/4}$

$\frac{1}{4^3} * \frac{4^1}{1}$

$\frac{4^1}{4^3}$

Hence:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{4^{1}}{4^{3}}$

Choosing the second:

$\dfrac{4^{-3}}{4^{-1}}$

Apply law of indices: $(\frac{a^m}{a^n} = a^{m-n})$

So,

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3-(-1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-3+1)}$

$\dfrac{4^{-3}}{4^{-1}} = 4^{-2}$

Apply law of indices: $(a^{-b} = \frac{1}{a^b})$

So:

$\dfrac{4^{-3}}{4^{-1}} = \dfrac{1}{4^{2}}$

4 0

3 years ago

An image point has coordinates B'(7,-4). Find the coordinates of its pre-image if the translation used was

Elza [17]

Answer:

Step-by-step explanation:

To go from B' to B , perform the inverse operation

That is the translation rule is (x - 4, y - 5 ) , then

B'(7, - 4 ) → B (7 - 4, - 4 - 5 ) → B (3, - 9 ) → option B

7 0

3 years ago

The new set of tires you will need for your car cost $320 you have $80 saved how much will you need to save each month to buy th

SOVA2 [1]

$80/month 320-80=240, then 240/3=80

5 0

3 years ago

R(x) = –x² + 3x s(x) = 2x + 1<br><br> (s – r)(x) =

natta225 [31]

r(x) = –x² + 3x

s(x) = 2x + 1

(s – r)(x) is simply the difference of these functions. Subtract r(x) from s(x):

(s - r)(x) = s(x) - r(x)

(s - r)(x) = 2x + 1 - (-x² + 3x)

(s - r)(x) = 2x + 1 + x² - 3x

(s - r)(x) = x² - x + 1

3 0

3 years ago

Read 2 more answers

What are the solutions to 2x^2-4x-30=0

oksano4ka [1.4K]

Answer:

ill try 2x2-4x-30=0

Two solutions were found :

x = 5

x = -3

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(2x2 - 4x) - 30 = 0

5 0

4 years ago