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3 years ago

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The number p and 2/3 are additive inverses. Drag and drop 2/3 and p to their correct positions on the number line. Drag and drop

the label "Sum" to the sum of 2/3 and p.

1 answer:

MatroZZZ [7]3 years ago

4 0

Answer:

$p=-\frac{2}{3}$

Step-by-step explanation:

If p and 2/3 are additive inverse, then p must be equal to $-\frac{2}{3}$ .

Because an additive inverse is a number that added to another, it results in zero. So, in this case p is the opposite number of 2/3.

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If tanA=a <br>then find sin4A-2sin2A/ sin4A+2sin2A

anygoal [31]

Answer:

The value of the given expression is

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

Step by step Explanation:

Given that $tanA=a$

To find the value of $\frac{sin4A-2sin2A}{sin4A+2sin2A}$

Let us find the value of the expression :

$\frac{sin4A-2sin2A}{sin4A+2sin2A}=\frac{2cos2Asin2A-2sin2A}{2cos2Asin2A+2sin2A}$ ( by using the formula $sin2A=2cosAsinA$ here A=2A)

$=\frac{2sin2A(cos2A-1)}{2sin2A(cos2A+1)}$

$=\frac{(cos2A-1)}{(cos2A+1)}$

$=\frac{(-(1-cos2A))}{(1+cos2A)}$ (using $sin^2A+cos^2A=1$ here A=2A)

$=\frac{-(sin^2A+cos^2A-(cos^2A-sin^2A))}{sin^2A+cos^2A+(cos^2A-sin^2A)}$ (using $cos2A=cos^2A-sin^2A$ here A=2A)

$=\frac{-(sin^2A+cos^2A-cos^2A+sin^2A)}{sin^2A+cos^2A+(cos^2A-sin^2A)}$

$=\frac{-(sin^2A+sin^2A)}{cos^2A+cos^2A}$

$=\frac{-2sin^2A}{2cos^2A}$

$=-\frac{sin^2A}{cos^2A}$

$=-tan^2A$ ( using $tanA=\frac{sinA}{cosA}$ here A=2A )

$=-a^2$ (since tanA=a given )

Therefore $\frac{sin4A-2sin2A}{sin4A+2sin2A}=-a^2$

6 0

3 years ago

What are the factors of 2x2 + 3x – 54? Select two options. 2x – 9 2x – 6 2x + 6 x – 6 x + 6

andrew-mc [135]

Answer:

2x − 9 and x + 6

Step-by-step explanation:

2x² + 3x − 54

Factor using the AC method.

2 × -54 = -108

Factors of -108 that add up to 3 are +12 and -9.

Divide by 2 and reduce: 12/2 = 6/1, -9/2 = -9/2.

Therefore, the factors are x + 6 and 2x − 9.

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