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Mashcka [7]
2 years ago
14

HELP PLZ I'M CONFUSED

Mathematics
2 answers:
SVEN [57.7K]2 years ago
6 0
<span>4 + 3 + 7 ? 7 + 0 +7 

</span>4 + 3 + 7 = 14
7 + 0 +7  = 14
so

4 + 3 + 7  =  7 + 0 +7 
answer
<span>D. =</span>
alukav5142 [94]2 years ago
3 0
.........the answer is D. =
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Please help me i need to finish this i’m tired (please use grid if you can) asap!!!
jasenka [17]

The linear equation is y = 4x - 4

And the graph of the linear equation can be seen in the image below.

<h3>How to graph the last line?</h3>

It seems that you already are good at graphing, so I will try to explain how to find the equation more in detail.

Remember that a general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

In this case, we know that the y-intercept is -4, then b = -4, replacing that we get:

y = a*x - 4

Now we also can see that this line passes through the point (2, 4), this means that if we evaluate in x = 2, the outcome should be y = 4, replacing that we get:

4 = a*2  - 4

4 + 4 = a*2

8 = a*2

8/2 = a = 4

Then the slope is 4, and the linear equation is:

y = 4x - 4

The graph is below.

If you want to learn more about linear functions:

brainly.com/question/4025726

#SPJ1

8 0
1 year ago
What is the sum of the first seven terms of the geometric series where a1 = 10 and r = −2?
matrenka [14]
Sum_{7} = 10 *  \frac{1- (-2^{7}) }{1 - (-2)} =  10*  \frac{1+128}{1+2} = 10*  \frac{129}{3} =   10 * 43 = 430
4 0
2 years ago
if you have budgeted 12% of your monthly income for groceries how much can you spend on groceries if you earn $950 bi-weekly
finlep [7]
Well if you make 950 dollars every two weeks, in a month you will have 1,900. Then take 12% of 1,900, and you will have 228 dollars to spend a month on groceries.
7 0
3 years ago
Read 2 more answers
I don’t know how to do this
stich3 [128]

To check for continuity at the edges of each piece, you need to consider the limit as x approaches the edges. For example,

g(x)=\begin{cases}2x+5&\text{for }x\le-3\\x^2-10&\text{for }x>-3\end{cases}

has two pieces, 2x+5 and x^2-10, both of which are continuous by themselves on the provided intervals. In order for g to be continuous everywhere, we need to have

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3^+}g(x)=g(-3)

By definition of g, we have g(-3)=2(-3)+5=-1, and the limits are

\displaystyle\lim_{x\to-3^-}g(x)=\lim_{x\to-3}(2x+5)=-1

\displaystyle\lim_{x\to-3^+}g(x)=\lim_{x\to-3}(x^2-10)=-1

The limits match, so g is continuous.

For the others: Each of the individual pieces of f,h are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.

4 0
3 years ago
AWSER PLASE IM STUCK ON THIS
dolphi86 [110]
1) 4 2/5 +1/5 = D)4 3/5
2)5 6/9- 1/3 = 5 1/3 or 16/3
3 0
2 years ago
Read 2 more answers
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