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3 years ago

6.

Mathematics

2 answers:

spin [16.1K]3 years ago

7 0

The number is 3947

It should be noted that 36 hundreds will be equal to:

= 36 × 100

= 3600

It should be noted that 34 tens will be:

= 34 × 10

= 340

7 ones will be:

= 7 × 1

= 7.

Therefore, the sum will be:

= 3600 + 340 + 7 = 3947

guajiro [1.7K]3 years ago

3 0

Answer:

3947

Step-by-step explanation:

You might be interested in

What is the probability of getting zero heads in six tosses? What is the probability of getting exactly two heads in six tosses?

alexira [117]

Answer:

The probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is 0.234375.

Step-by-step explanation:

Using the Minitab software for computing the desired probabilities.

We take n=6 and p=1/2 because we have six tosses and in binomial distribution the probability of success p remains constant in each trial whereas the probability of success in this case is getting heads.

When a coin is tossed then there are two possible outcomes head or tail.

So,

p= P(heads)=1/2=0.5

The probability of getting zero heads in six tosses is computed by considering the following steps:

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=0 and bubble the probability and by clicking OK we get the following output:

Probability Density Function

Binomial with n = 6 and p = 0.5

x P( X = x )

0 0.015625

So, the probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is computed by considering the following steps :

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=2 and bubble the probability and by clicking OK we get the following output:

Probability Density Function

Binomial with n = 6 and p = 0.5

x P( X = x )

2 0.234375

So, the probability of getting exactly two heads in six tosses is 0.234375.

7 0

4 years ago

30/49(-63/40) please solve

Allisa [31]

Answer:

-27/28

hope this helps :D have a good day

7 0

3 years ago

Read 2 more answers

Lamont works for an electric utility and is installing a 40 foot utility pole as shown. Lamont drills the anchor of a support ca

PIT_PIT [208]

Answer:

Approximately 43 feet of minimum cable is needed.

Step-by-step explanation:

This problem can be solved using Trigonometry and Pythagorean theorem. Pythagorean theorem applies on right-triangles (which are known to have one 90° angle). The theorem states that the square of the Hypotenuse is obtained by the squared sum of the other two sides of the triangle (i.e the two sides forming the 90° angle - with the hypotenuse side being across it as:

$h^2=a^2+b^2$ Eqn. (1)

where

$h$ is the hypotenuse

$a$ is a side

$b$ is a side

Now in this case, the utility pole must be perpendicular to the ground and the anchor being parallel to the ground, and a 90° angle formed between them. Conclusively the cable length will be represented by the hypotenuse in a right triangle. So here we have $a=40ft$ and $b=15ft$ . Plugging in Eqn.(1) and solving for $h$ we have: