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erik [133]
3 years ago
7

Reflection across y=2 J(1,3) U(0,5) R(1,5) C(3,2)

Mathematics
1 answer:
VladimirAG [237]3 years ago
5 0

no rurio greob tryo yeu


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find the domain of y equals 4 multiplied by the square root of the quantity 4 multiplied by x plus 2 end of quantity. a. x is gr
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y=4\sqrt{4(x+2)}\\\\D:4(x+2)\geq 0\ \ \ |divide\ both\ sides\ by\ 4\\\\x+2\geq0\ \ \ |subtract\ 2\ from\ both\ sides\\\\\boxed{x\geq-2}\to\boxed{c.}
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The quotient of number and 3 is the same as difference of the number<br>​
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x÷3=y

9÷3=6

9-3=6

so the answer is 9

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Christopher has a credit card with an APR of 13.13%. The card uses the adjusted balance method to calculate finance charges. The
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3 years ago
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If t a n squared θ = 3 /8 , what is the value of  s e c θ
TEA [102]

We can use 3 facts:

\tan{\theta}=\frac{y}{x}

\sec{\theta}=\frac{r}{x}

x^2+y^2=r^2

So, to find our x and our y we can do:

\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}So, now that we know our x and our y we can find our r.

(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}

You'll notice, though, that there were two solutions for \tan{\theta}, which means we have a positive and a negative for our x. So:

\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}

7 0
3 years ago
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Can someone help me with this<br> giving out brainliest
wel

Answer:

C

Step-by-step explanation:

Step 1: plot your 2 known points, (-2,3) and (1,0)

Step 2: after that, you should see that your y value should be a - and your x a +. You can eliminate A and B.

Step 3: check to see if C is a correct answer, (4,-3)

C is the answer, hope that helps

8 0
3 years ago
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