Answer:
Rate = 14.07%
Step-by-step explanation:
A= 3500
P= 2000
n = 12
t = 4
![3500= 2000(1+\frac{r}{12})^{4 \times 12}\\\\\frac{3500}{2000} = (1+\frac{r}{12})^{48}\\\\\frac{7}{4} = (1+\frac{r}{12})^{48}\\\\1.75 = (1+\frac{r}{12})^{48}\\\\\sqrt[48]{1.75} = (1+\frac{r}{12})\\\\\sqrt[48]{1.75}-1 = \frac{r}{12}\\\\0.01172688 = \frac{r}{12}\\\\r = 0.01172688 \times 12 = 0.14072267\\\\r \% = 14.07%](https://tex.z-dn.net/?f=3500%3D%202000%281%2B%5Cfrac%7Br%7D%7B12%7D%29%5E%7B4%20%5Ctimes%2012%7D%5C%5C%5C%5C%5Cfrac%7B3500%7D%7B2000%7D%20%3D%20%281%2B%5Cfrac%7Br%7D%7B12%7D%29%5E%7B48%7D%5C%5C%5C%5C%5Cfrac%7B7%7D%7B4%7D%20%3D%20%281%2B%5Cfrac%7Br%7D%7B12%7D%29%5E%7B48%7D%5C%5C%5C%5C1.75%20%3D%20%281%2B%5Cfrac%7Br%7D%7B12%7D%29%5E%7B48%7D%5C%5C%5C%5C%5Csqrt%5B48%5D%7B1.75%7D%20%20%3D%20%281%2B%5Cfrac%7Br%7D%7B12%7D%29%5C%5C%5C%5C%5Csqrt%5B48%5D%7B1.75%7D-1%20%3D%20%5Cfrac%7Br%7D%7B12%7D%5C%5C%5C%5C0.01172688%20%3D%20%5Cfrac%7Br%7D%7B12%7D%5C%5C%5C%5Cr%20%3D%200.01172688%20%5Ctimes%2012%20%3D%200.14072267%5C%5C%5C%5Cr%20%5C%25%20%3D%2014.07%25)
Answer:
X=17.5
Step-by-step explanation:
The solution is in the image
Answer:
f(-3) = -2
f(-2.6) = -2
f(0.6) = 2.4
f(4.5) = 8.5
Step-by-step explanation:
(Whole question:
Evaluate the piecewise function for the given values.
Find f(-3), f(-2,6), f(0.6), and f(4.5) for f(x)={ -2 If x ≤ 0 4x. If 0 <x <1. x + 4. If x ≥ 1)
As the piecewise function shows, the function f(x) has the value of -2 for values of x lesser or equal than 0, has the value of 4x if the value of x is between 0 and 1, and has the value of x+4 for values of x greater or equal than 1.
So, for f(-3), the value of x is lesser than 0, so we have that f(-3) = -2
For f(-2.6), the value of x is lesser than 0, so we have that f(-3) = -2
For f(0.6), the value of x is between 0 and 1, so we have that f(0.6) = 4*0.6 = 2.4
For f(4.5), the value of x is greater than 1, so we have that f(4.5) = 4.5 + 4 = 8.5
Answer:
c.
Step-by-step explanation:
2 lines are cut by a transversal. At the intersection of the first line with the transversal, the bottom right angle is 130 degrees. At the intersection of the second line with the transversal, the uppercase right angle is 50 degrees.
