<h3>
<u>Answer the following questions :-</u></h3>
Raja is junk seller. He sells many things. Here is given the list of junk.
Check the Raja's rate list and solve the following questions.

<h2>
<u>Solutions :-</u></h2>
1. How much money will you pay to Raju for 20 kg of newspapers?




<u>∴ We need to pay Rs.100 for buy 20 kg of newspapers. </u>

2. What is the cost of 5 kg Iron?




<u>∴ The cost of 5 kg iron is Rs.50.</u>

3. What is the cost of 9 kg Plastic?




<u>∴ The cost of 9 kg plastic is Rs.72. </u>

4. What is the cost of 7 kg Brass?



<u>∴ The cost of 7kg brass is Rs.350.</u>

Answer:
4= Sx+10/2 simplifies to -s*x-1=0
Step-by-step explanation:
There is two hundred and four (204) on a standard chessboard.
Answer:
The answer to your question is ( -7/10, -4 7/10)
Step-by-step explanation:
Data
Enpoint (3/2, 1 1/2) x1 = 3/2 y1 = 1 1/2
Midpoint (2/5, -8/5) xm = 2/5 ym = -8/5
Entpoint 2 ( x, y)
Formula
Xm = (x1 + x2)/2 Solve for x2 x2 = 2xm - x1
Ym = (y1 + y2)/2 Solve for y2 y2 = 2ym - y1
Substitution
x2 = 2(2/5) - 3/2
x2 = 4/5 - 3/2
x2 = (8 - 15)/10
x2 = -7/10
y2 = 2(-8/5) - 1 1/2
y2 = -16/5 - 3/2
y2 = (-32 - 15) / 10
y2 = -47/10 = -4 7/10