<h3><u>
Answer:</u></h3>
The jars that Ming can use are:
Jar A
Jar C
and Jar D
<h3><u>
Step-by-step explanation:</u></h3>
Ming needs 1/2 pint of red paint for an art project.
He has 6 jars that have the following amounts of red paint in them:
A. 2/3 pint
B. 1/4 pint
C. 4/6 pint
D. 3/4 pint
E. 3/8 pint
F. 2/6 pint
He wants to use only 1 jar of paint.
i.e. the jar which has less than 1/2 pint of paint can't be used.
<u>A jar:</u>
It has 2/3 pint of paint now we need to check whether this quantity is less than or grater than equal to 1/2.
We try to make the denominator same of both the quantities.
As:
2/3=4/6
Also 1/2=3/6
Since, 4/6> 3/6
hence A jar could be used.
<u>B jar:</u>
It has 1/4 pint of paint.
As 1/2=2/4
Also 1/4<2/4.
Hence Jar B can't be used.
<u>C jar:</u>
It has 4/6 pint of paint.
As 1/2=3/6
Now 4/6> 3/6
Hence jar C could be used.
<u>D jar:</u>
3/4 pint.
as 1/2=2/4
Hence, 3/4>2/4
Hence, jar D could be used.
<u>E jar:</u>
It has 3/8 pint of paint.
As 1/2=4/8
As 3/8<4/8
Hence jar E can't be used.
<u>F jar:</u>
It has 2/6 pint of paint.
As 1/2=3/6
Hence, 2/6<3/6
Hence, jar F can't be used.