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Savatey [412]
3 years ago
10

Ming needs 1/2 pint of red paint for an art project. He has 6 jars that have the following amounts of red paint in them. He want

s to use only 1 jar of paint. Mark all the jars of paints that Ming can use. *There is more that 1 answer* A. 2/3 pint B.1/4 pint C.4/6 pint D.3/4 pint E. 3/8 pint F.2/6 pint
Mathematics
2 answers:
VikaD [51]3 years ago
7 0
<h3><u>Answer:</u></h3>

The jars that Ming can use are:

Jar A

Jar C

and Jar D

<h3><u>Step-by-step explanation:</u></h3>

Ming needs 1/2 pint of red paint for an art project.

He has 6 jars that have the following amounts of red paint in them:

A. 2/3 pint

B. 1/4 pint

C. 4/6 pint

D. 3/4 pint

E.  3/8 pint

F. 2/6 pint

He wants to use only 1 jar of paint.

i.e. the jar which has less than 1/2 pint of paint can't be used.

<u>A jar:</u>

It has 2/3 pint of paint now we need to check whether this quantity is less than or grater than equal to 1/2.

We try to make the denominator same of both the quantities.

As:

2/3=4/6

Also 1/2=3/6

Since, 4/6> 3/6

hence A jar could be used.

<u>B jar:</u>

It has 1/4 pint of paint.

As 1/2=2/4

Also 1/4<2/4.

Hence Jar B can't be used.

<u>C jar:</u>

It has 4/6 pint of paint.

As 1/2=3/6

Now 4/6> 3/6

Hence jar C could be used.

<u>D jar:</u>

3/4 pint.

as 1/2=2/4

Hence, 3/4>2/4

Hence, jar D could be used.

<u>E jar:</u>

It has 3/8 pint of paint.

As 1/2=4/8

As 3/8<4/8

Hence jar E can't be used.

<u>F jar:</u>

It has 2/6 pint of paint.

As 1/2=3/6

Hence, 2/6<3/6

Hence, jar F can't be used.

Dmitrij [34]3 years ago
5 0
The possible answers are A C and D because they all have at least a half pint of paint.
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Múltiplos de 1600:

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