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Savatey [412]
3 years ago
10

Ming needs 1/2 pint of red paint for an art project. He has 6 jars that have the following amounts of red paint in them. He want

s to use only 1 jar of paint. Mark all the jars of paints that Ming can use. *There is more that 1 answer* A. 2/3 pint B.1/4 pint C.4/6 pint D.3/4 pint E. 3/8 pint F.2/6 pint
Mathematics
2 answers:
VikaD [51]3 years ago
7 0
<h3><u>Answer:</u></h3>

The jars that Ming can use are:

Jar A

Jar C

and Jar D

<h3><u>Step-by-step explanation:</u></h3>

Ming needs 1/2 pint of red paint for an art project.

He has 6 jars that have the following amounts of red paint in them:

A. 2/3 pint

B. 1/4 pint

C. 4/6 pint

D. 3/4 pint

E.  3/8 pint

F. 2/6 pint

He wants to use only 1 jar of paint.

i.e. the jar which has less than 1/2 pint of paint can't be used.

<u>A jar:</u>

It has 2/3 pint of paint now we need to check whether this quantity is less than or grater than equal to 1/2.

We try to make the denominator same of both the quantities.

As:

2/3=4/6

Also 1/2=3/6

Since, 4/6> 3/6

hence A jar could be used.

<u>B jar:</u>

It has 1/4 pint of paint.

As 1/2=2/4

Also 1/4<2/4.

Hence Jar B can't be used.

<u>C jar:</u>

It has 4/6 pint of paint.

As 1/2=3/6

Now 4/6> 3/6

Hence jar C could be used.

<u>D jar:</u>

3/4 pint.

as 1/2=2/4

Hence, 3/4>2/4

Hence, jar D could be used.

<u>E jar:</u>

It has 3/8 pint of paint.

As 1/2=4/8

As 3/8<4/8

Hence jar E can't be used.

<u>F jar:</u>

It has 2/6 pint of paint.

As 1/2=3/6

Hence, 2/6<3/6

Hence, jar F can't be used.

Dmitrij [34]3 years ago
5 0
The possible answers are A C and D because they all have at least a half pint of paint.
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Solve this system of equations. <br><br> 12x − 18y = 27 <br> 4x − 6y = 10
kifflom [539]

Answer:

no solution

Step-by-step explanation:

12x − 18y = 27  

4x − 6y = 10

Multiply the second equation by -3 so we can eliminate x

-3(4x − 6y) = 10*-3

-12x +18y = -30

Add the first equation to this new equation

12x − 18y = 27

-12x +18y = -30

------------------------

0 = -3

This is not a true equation, so there is no solution


7 0
3 years ago
If Jaime is riding at 14 miles per hour and Cori is riding at 0.40 km per minute, how far will each of them bike in two hours? 1
user100 [1]

Answer:

just take speed =distance ÷time

dustance is speedxtime

14x1.61=22.54÷60 to change to min =0.37km per minute

0.40x0.37= 0.148 km

perhaps I may get wrong

5 0
3 years ago
SOMEONE PLS HELP WILL GIVE BRAINLIEST ANSWER IF CORRECT
Viktor [21]
I don't see the picture what is it about?
7 0
3 years ago
Read 2 more answers
Pls help.....................
scZoUnD [109]

Answer:

351 carrots

Step-by-step explanation:

13 = 1 tens + 3 units

27 = 2 tens + 7 units

<h3>13 × 27</h3>

13 × 27 = 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27

13 × 27 = 351

Conclusion:

Total Carrots is 351 carrots.

4 0
2 years ago
The triangle T has vertices at (-2, 1), (2, 1) and (0,-1). (It might be an idea to
Firdavs [7]

Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:

<em>y</em> = -1 - <em>x</em>  ==>  <em>x</em> = -1 - <em>y</em>

<em>y</em> = <em>x</em> - 1  ==>  <em>x</em> = 1 + <em>y</em>

So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.

This means the area is given by the integral,

\displaystyle\iint_T\mathrm dA=\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy

The integral with respect to <em>x</em> is trivial:

\displaystyle\int_{-1}^1\int_{-1-y}^{1+y}\mathrm dx\,\mathrm dy=\int_{-1}^1x\bigg|_{-1-y}^{1+y}\,\mathrm dy=\int_{-1}^1(1+y)-(-1-y)\,\mathrm dy=2\int_{-1}^1(1+y)\,\mathrm dy

For the remaining integral, integrate term-by-term to get

\displaystyle2\int_{-1}^1(1+y)\,\mathrm dy=2\left(y+\frac{y^2}2\right)\bigg|_{-1}^1=2\left(1+\frac12\right)-2\left(-1+\frac12\right)=\boxed{4}

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.

6 0
3 years ago
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